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Math
Math Statement
Problem 23601
Solve the equation
∣
3
k
−
2
∣
=
2
∣
k
+
2
∣
|3 k-2|=2|k+2|
∣3
k
−
2∣
=
2∣
k
+
2∣
.
See Solution
Problem 23602
Find the measure of
∠
2
\angle 2
∠2
if
m
∠
1
=
(
2
x
+
29
)
∘
\mathrm{m} \angle 1=(2 x+29)^{\circ}
m
∠1
=
(
2
x
+
29
)
∘
and
m
∠
2
=
(
3
x
−
17
)
∘
\mathrm{m} \angle 2=(3 x-17)^{\circ}
m
∠2
=
(
3
x
−
17
)
∘
.
See Solution
Problem 23603
Simplify the expression:
1
cos
θ
−
cos
θ
\frac{1}{\cos \theta}-\cos \theta
c
o
s
θ
1
−
cos
θ
.
See Solution
Problem 23604
Add and simplify:
sin
θ
cos
θ
+
1
sin
θ
\frac{\sin \theta}{\cos \theta}+\frac{1}{\sin \theta}
cos
θ
sin
θ
+
sin
θ
1
.
See Solution
Problem 23605
Multiply and simplify:
(
sin
θ
+
5
)
(
sin
θ
+
6
)
(\sin \theta+5)(\sin \theta+6)
(
sin
θ
+
5
)
(
sin
θ
+
6
)
See Solution
Problem 23606
Multiply and simplify:
(
1
−
sin
θ
)
(
1
+
sin
θ
)
(1-\sin \theta)(1+\sin \theta)
(
1
−
sin
θ
)
(
1
+
sin
θ
)
.
See Solution
Problem 23607
Multiply and simplify:
(
4
cos
θ
+
5
)
(
7
cos
θ
−
2
)
(4 \cos \theta + 5)(7 \cos \theta - 2)
(
4
cos
θ
+
5
)
(
7
cos
θ
−
2
)
.
See Solution
Problem 23608
Multiply and simplify:
(
2
−
tan
θ
)
(
2
+
tan
θ
)
(2-\tan \theta)(2+\tan \theta)
(
2
−
tan
θ
)
(
2
+
tan
θ
)
.
See Solution
Problem 23609
Prove that
cos
θ
tan
θ
=
sin
θ
\cos \theta \tan \theta = \sin \theta
cos
θ
tan
θ
=
sin
θ
is an identity by simplifying the left side.
See Solution
Problem 23610
Simplify the expression
(
sin
θ
−
cos
θ
)
2
(\sin \theta - \cos \theta)^{2}
(
sin
θ
−
cos
θ
)
2
.
See Solution
Problem 23611
Prove the identity
sin
θ
sec
θ
cot
θ
=
1
\sin \theta \sec \theta \cot \theta = 1
sin
θ
sec
θ
cot
θ
=
1
by simplifying the left side using
sin
θ
\sin \theta
sin
θ
and
cos
θ
\cos \theta
cos
θ
.
See Solution
Problem 23612
Prove that
csc
θ
cot
θ
=
sec
θ
\frac{\csc \theta}{\cot \theta}=\sec \theta
c
o
t
θ
c
s
c
θ
=
sec
θ
by simplifying the left side to match the right side.
See Solution
Problem 23613
Simplify
x
2
−
16
\sqrt{x^{2}-16}
x
2
−
16
after substituting
x
=
4
sec
(
θ
)
x = 4 \sec(\theta)
x
=
4
sec
(
θ
)
, where
0
∘
<
θ
<
9
0
∘
0^{\circ}<\theta<90^{\circ}
0
∘
<
θ
<
9
0
∘
.
See Solution
Problem 23614
Simplify the expression:
sec
θ
cot
θ
csc
θ
\frac{\sec \theta \cot \theta}{\csc \theta}
c
s
c
θ
s
e
c
θ
c
o
t
θ
. Show that it equals 1.
See Solution
Problem 23615
Prove the identity:
(
1
−
cos
θ
)
(
1
+
cos
θ
)
=
sin
2
θ
(1-\cos \theta)(1+\cos \theta)=\sin ^{2} \theta
(
1
−
cos
θ
)
(
1
+
cos
θ
)
=
sin
2
θ
by simplifying the left side.
See Solution
Problem 23616
Prove the identity:
csc
θ
−
sin
θ
=
cos
2
θ
sin
θ
\csc \theta - \sin \theta = \frac{\cos^{2} \theta}{\sin \theta}
csc
θ
−
sin
θ
=
s
i
n
θ
c
o
s
2
θ
. Simplify the left side.
See Solution
Problem 23617
Prove the identity:
cos
θ
sec
θ
+
sin
θ
csc
θ
=
1
\frac{\cos \theta}{\sec \theta}+\frac{\sin \theta}{\csc \theta}=1
s
e
c
θ
c
o
s
θ
+
c
s
c
θ
s
i
n
θ
=
1
by simplifying the left side.
See Solution
Problem 23618
Simplify the expression
sin
θ
+
1
cos
θ
\sin \theta+\frac{1}{\cos \theta}
sin
θ
+
c
o
s
θ
1
.
See Solution
Problem 23619
Simplify
9
−
x
2
\sqrt{9-x^{2}}
9
−
x
2
by substituting
x
=
3
sin
(
θ
)
x=3 \sin (\theta)
x
=
3
sin
(
θ
)
, where
0
∘
<
θ
<
9
0
∘
0^{\circ}<\theta<90^{\circ}
0
∘
<
θ
<
9
0
∘
.
See Solution
Problem 23620
Find the value of
f
(
1
)
f(1)
f
(
1
)
for the function
f
(
x
)
=
9.1
x
2
+
0.5
x
f(x)=9.1 x^{2}+0.5 x
f
(
x
)
=
9.1
x
2
+
0.5
x
. Provide your answer as a decimal or whole number.
See Solution
Problem 23621
Create a truth table for the expression
∼
(
q
↔
∼
p
)
\sim(q \leftrightarrow \sim p)
∼
(
q
↔∼
p
)
.
See Solution
Problem 23622
Determine if the statement
(
p
∧
q
)
∧
(
∼
p
∨
∼
q
)
(p \wedge q) \wedge(\sim p \vee \sim q)
(
p
∧
q
)
∧
(
∼
p
∨
∼
q
)
is a tautology, self-contradiction, or neither using a truth table.
See Solution
Problem 23623
Show that
log
3
x
+
log
9
x
=
3
lg
x
2
lg
3
\log _{3} x+\log _{9} x=\frac{3 \lg x}{2 \lg 3}
lo
g
3
x
+
lo
g
9
x
=
2
l
g
3
3
l
g
x
and solve
log
3
x
+
log
9
x
=
4
\log _{3} x+\log _{9} x=4
lo
g
3
x
+
lo
g
9
x
=
4
.
See Solution
Problem 23624
Calculate the significant figures for the result of
4.5
×
1
0
14
/
8.3
×
1
0
8
.
4.5 \times 10^{14} / 8.3 \times 10^{8}.
4.5
×
1
0
14
/8.3
×
1
0
8
.
See Solution
Problem 23625
Convert
4.5
m
3
4.5 \mathrm{~m}^{3}
4.5
m
3
to
L
\mathrm{L}
L
.
See Solution
Problem 23626
Calculate
6.2
×
1
0
−
13
×
5.68
×
1
0
8
6.2 \times 10^{-13} \times 5.68 \times 10^{8}
6.2
×
1
0
−
13
×
5.68
×
1
0
8
and report the answer with the correct significant figures.
See Solution
Problem 23627
Prove that
log
3
x
+
log
9
x
=
3
lg
x
2
lg
3
\log _{3} x+\log _{9} x=\frac{3 \lg x}{2 \lg 3}
lo
g
3
x
+
lo
g
9
x
=
2
l
g
3
3
l
g
x
.
See Solution
Problem 23628
Find the tangent line equation to the curve
y
=
−
x
2
+
5
x
−
4
y=-x^{2}+5x-4
y
=
−
x
2
+
5
x
−
4
at
x
=
1
x=1
x
=
1
.
See Solution
Problem 23629
Prove that
sin
θ
2
−
1
+
sin
θ
cos
θ
2
−
1
+
sin
θ
=
cot
θ
2
\frac{\sin \frac{\theta}{2}-\sqrt{1+\sin \theta}}{\cos \frac{\theta}{2}-\sqrt{1+\sin \theta}}=\cot \frac{\theta}{2}
c
o
s
2
θ
−
1
+
s
i
n
θ
s
i
n
2
θ
−
1
+
s
i
n
θ
=
cot
2
θ
.
See Solution
Problem 23630
Find the values of the following Fibonacci numbers:
F
22
,
F
46
,
F
20
,
F
12
,
F
18
,
F
6
,
F
28
,
F
19
,
F
25
,
F
10
F_{22}, F_{46}, F_{20}, F_{12}, F_{18}, F_{6}, F_{28}, F_{19}, F_{25}, F_{10}
F
22
,
F
46
,
F
20
,
F
12
,
F
18
,
F
6
,
F
28
,
F
19
,
F
25
,
F
10
.
See Solution
Problem 23631
Find the reflection of the line
x
=
4
x=4
x
=
4
across the
y
y
y
-axis.
See Solution
Problem 23632
Find the limit as
x
x
x
approaches 4 for the expression
x
3
+
x
x^{3}+x
x
3
+
x
.
See Solution
Problem 23633
Identify equivalent equations for
p
−
q
=
−
93
p-q=-93
p
−
q
=
−
93
. Which of these are equivalent?
1.
p
−
q
3
=
−
31
\frac{p-q}{3}=-31
3
p
−
q
=
−
31
2.
p
−
q
3
=
−
32
\frac{p-q}{3}=-32
3
p
−
q
=
−
32
3.
p
−
q
−
3
=
29
\frac{p-q}{-3}=29
−
3
p
−
q
=
29
4.
p
−
q
−
3
=
31
\frac{p-q}{-3}=31
−
3
p
−
q
=
31
See Solution
Problem 23634
Identify equivalent equations to
15
=
t
−
u
15=t-u
15
=
t
−
u
from the options:
20
=
t
−
u
+
5
20=t-u+5
20
=
t
−
u
+
5
,
17
=
2
+
t
−
u
17=2+t-u
17
=
2
+
t
−
u
,
18
=
t
−
u
+
3
18=t-u+3
18
=
t
−
u
+
3
,
19
=
t
−
u
+
4
19=t-u+4
19
=
t
−
u
+
4
.
See Solution
Problem 23635
Identify all equations equivalent to:
−
30
=
14
y
-30=14 y
−
30
=
14
y
. Consider properties of equality. Options:
60
=
−
2
⋅
14
y
60=-2 \cdot 14 y
60
=
−
2
⋅
14
y
,
−
60
=
14
y
⋅
2
-60=14 y \cdot 2
−
60
=
14
y
⋅
2
,
90
=
14
y
⋅
−
3
90=14 y \cdot-3
90
=
14
y
⋅
−
3
,
−
90
=
14
y
⋅
3
-90=14 y \cdot 3
−
90
=
14
y
⋅
3
.
See Solution
Problem 23636
Find all equations equivalent to
12
=
4
c
12=4c
12
=
4
c
using properties of equality:
2
=
4
c
−
10
2=4c-10
2
=
4
c
−
10
,
9
=
4
c
−
2
9=4c-2
9
=
4
c
−
2
,
10
=
4
c
−
2
10=4c-2
10
=
4
c
−
2
,
4
=
4
c
−
8
4=4c-8
4
=
4
c
−
8
.
See Solution
Problem 23637
Find all equations equivalent to:
−
62
=
r
+
s
-62 = r + s
−
62
=
r
+
s
. Consider the following options.
See Solution
Problem 23638
Select equations equivalent to
15
=
r
+
s
15 = r + s
15
=
r
+
s
using properties of equality:
20
=
r
+
s
+
5
20 = r + s + 5
20
=
r
+
s
+
5
,
19
=
4
+
r
+
s
19 = 4 + r + s
19
=
4
+
r
+
s
,
18
=
3
+
r
+
s
18 = 3 + r + s
18
=
3
+
r
+
s
,
17
=
r
+
s
+
2
17 = r + s + 2
17
=
r
+
s
+
2
.
See Solution
Problem 23639
Find pairs of factors for 50 and complete the equations: 50 = 2 \cdot 15, 50 = __.
See Solution
Problem 23640
Find the prime factorization of 10 and list the factors in ascending order (e.g.,
2
×
5
2 \times 5
2
×
5
).
See Solution
Problem 23641
Find all factor pairs for 16 and complete the equations:
16
=
1
⋅
16
16
=
2
⋅
8
16
=
16=1 \cdot 16 \\ 16=2 \cdot 8 \\ 16=
16
=
1
⋅
16
16
=
2
⋅
8
16
=
See Solution
Problem 23642
Solve the equation
log
2
x
−
log
2
7
=
log
2
(
x
−
1
)
\log _{2} x - \log _{2} 7 = \log _{2}(x - 1)
lo
g
2
x
−
lo
g
2
7
=
lo
g
2
(
x
−
1
)
.
See Solution
Problem 23643
Solve the system of equations using an inverse matrix and show the inverse matrix
A
−
1
A^{-1}
A
−
1
used.
2
x
−
3
y
=
−
8
2x - 3y = -8
2
x
−
3
y
=
−
8
−
4
x
+
y
=
−
2
-4x + y = -2
−
4
x
+
y
=
−
2
See Solution
Problem 23644
Find two equations that equal 48 using multiplication, similar to:
48
=
1
⋅
48
48 = 1 \cdot 48
48
=
1
⋅
48
,
48
=
2
⋅
24
48 = 2 \cdot 24
48
=
2
⋅
24
.
See Solution
Problem 23645
Find the vertices and foci of the hyperbola
y
2
49
−
x
2
36
=
1
\frac{y^{2}}{49}-\frac{x^{2}}{36}=1
49
y
2
−
36
x
2
=
1
. Enter as
(
0
,
±
a
)
(0, \pm a)
(
0
,
±
a
)
and
(
0
,
±
c
)
(0, \pm c)
(
0
,
±
c
)
.
See Solution
Problem 23646
Solve the inequality:
log
3
5
(
2
−
x
)
+
log
3
5
(
x
+
2
)
>
log
3
5
3
x
\log _{\frac{3}{5}}(2-x)+\log _{\frac{3}{5}}(x+2)>\log _{\frac{3}{5}} 3 x
lo
g
5
3
(
2
−
x
)
+
lo
g
5
3
(
x
+
2
)
>
lo
g
5
3
3
x
.
See Solution
Problem 23647
Graph the hyperbola from the equation
25
x
2
−
36
y
2
−
900
=
0
25 x^{2}-36 y^{2}-900=0
25
x
2
−
36
y
2
−
900
=
0
using its transverse axis, vertices, and co-vertices.
See Solution
Problem 23648
Solve the inequality:
(
log
2
x
)
2
−
log
2
x
<
0
(\log_{2} x)^{2} - \log_{2} x < 0
(
lo
g
2
x
)
2
−
lo
g
2
x
<
0
.
See Solution
Problem 23649
Evaluate these limits: 1.
lim
x
→
4
(
x
3
+
x
)
\lim_{x \to 4}(x^3 + x)
lim
x
→
4
(
x
3
+
x
)
2.
lim
x
→
4
(
x
2
+
1
)
\lim_{x \to 4}(x^2 + 1)
lim
x
→
4
(
x
2
+
1
)
3.
lim
x
→
2
x
2
−
x
−
2
x
2
−
2
x
\lim_{x \to 2} \frac{x^2 - x - 2}{x^2 - 2x}
lim
x
→
2
x
2
−
2
x
x
2
−
x
−
2
4.
lim
x
→
1
x
2
−
2
x
+
1
x
3
−
x
\lim_{x \to 1} \frac{x^2 - 2x + 1}{x^3 - x}
lim
x
→
1
x
3
−
x
x
2
−
2
x
+
1
5.
lim
x
→
∞
x
2
+
1
x
2
\lim_{x \to \infty} \frac{\sqrt{x^2 + 1}}{x^2}
lim
x
→
∞
x
2
x
2
+
1
6.
lim
x
→
4
(
x
2
+
3
x
−
5
)
\lim_{x \to 4}(x^2 + 3x - 5)
lim
x
→
4
(
x
2
+
3
x
−
5
)
7.
lim
y
→
∞
(
y
3
−
2
y
+
7
)
\lim_{y \to \infty}(y^3 - 2y + 7)
lim
y
→
∞
(
y
3
−
2
y
+
7
)
8.
lim
t
→
0
2
t
2
+
1
t
3
+
3
t
−
4
\lim_{t \to 0} \frac{2t^2 + 1}{t^3 + 3t - 4}
lim
t
→
0
t
3
+
3
t
−
4
2
t
2
+
1
9.
lim
x
→
1
(
s
+
1
)
2
2
x
2
+
3
\lim_{x \to 1} \frac{(s + 1)^2}{2x^2 + 3}
lim
x
→
1
2
x
2
+
3
(
s
+
1
)
2
10.
lim
w
→
2
3
w
2
−
4
w
+
2
w
3
−
5
\lim_{w \to 2} \frac{3w^2 - 4w + 2}{w^3 - 5}
lim
w
→
2
w
3
−
5
3
w
2
−
4
w
+
2
11.
lim
w
→
−
1
3
w
2
−
2
w
+
7
w
2
+
1
\lim_{w \to -1} \frac{3w^2 - 2w + 7}{w^2 + 1}
lim
w
→
−
1
w
2
+
1
3
w
2
−
2
w
+
7
12.
lim
x
→
2
x
−
2
x
2
−
4
\lim_{x \to 2} \frac{\sqrt{x - 2}}{\sqrt{x^2 - 4}}
lim
x
→
2
x
2
−
4
x
−
2
13.
lim
x
→
2
(
1
−
x
2
)
1
(
1
−
x
2
)
2
\lim_{x \to 2} \frac{(1 - x^2)^{1}}{(1 - x^2)^2}
lim
x
→
2
(
1
−
x
2
)
2
(
1
−
x
2
)
1
14.
lim
x
→
3
x
−
3
x
2
−
9
\lim_{x \to 3} \frac{x - 3}{\sqrt{x^2 - 9}}
lim
x
→
3
x
2
−
9
x
−
3
15.
lim
x
→
∞
4
2
x
2
−
3
\lim_{x \to \infty} \frac{4}{2x^2 - 3}
lim
x
→
∞
2
x
2
−
3
4
16.
lim
x
→
∞
2
x
2
3
x
2
+
5
\lim_{x \to \infty} \frac{2x^2}{3x^2 + 5}
lim
x
→
∞
3
x
2
+
5
2
x
2
17.
lim
x
→
∞
x
2
3
x
2
−
4
x
+
1
\lim_{x \to \infty} \frac{x^2}{3x^2 - 4x + 1}
lim
x
→
∞
3
x
2
−
4
x
+
1
x
2
18.
lim
x
→
∞
2
3
x
\lim_{x \to \infty} 2^{\frac{3}{x}}
lim
x
→
∞
2
x
3
19.
lim
x
→
0
+
2
1
x
\lim_{x \to 0^+} 2^{\frac{1}{x}}
lim
x
→
0
+
2
x
1
20.
lim
x
→
0
+
1
1
+
2
1
x
\lim_{x \to 0^+} \frac{1}{1 + 2^{\frac{1}{x}}}
lim
x
→
0
+
1
+
2
x
1
1
See Solution
Problem 23650
Risolvi la disequazione:
472
(
log
2
x
)
2
−
log
2
x
<
0
472\left(\log _{2} x\right)^{2}-\log _{2} x<0
472
(
lo
g
2
x
)
2
−
lo
g
2
x
<
0
.
See Solution
Problem 23651
Find the asymptotes of the hyperbola:
(
y
+
1
)
2
9
−
(
x
−
2
)
2
64
=
1
\frac{(y+1)^{2}}{9}-\frac{(x-2)^{2}}{64}=1
9
(
y
+
1
)
2
−
64
(
x
−
2
)
2
=
1
.
See Solution
Problem 23652
Solve the inequality:
log
2
x
−
7
log
x
+
12
<
0
\log ^{2} x - 7 \log x + 12 < 0
lo
g
2
x
−
7
lo
g
x
+
12
<
0
.
See Solution
Problem 23653
Find the average rate of change of
y
=
2
×
3
x
y=2 \times 3^{x}
y
=
2
×
3
x
from
x
=
0
x=0
x
=
0
to
x
=
4
x=4
x
=
4
. Options: A 40.5 B 162 C 158 D 40 E 4
See Solution
Problem 23654
Find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
for
y
=
2
x
4
+
9
x
2
4
x
y=\frac{2 x^{4}+9 x^{2}}{4 x}
y
=
4
x
2
x
4
+
9
x
2
. Choices include options A to E.
See Solution
Problem 23655
Find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
for
y
=
2
x
4
+
9
x
2
4
x
y=\frac{2 x^{4}+9 x^{2}}{4 x}
y
=
4
x
2
x
4
+
9
x
2
. Options: A, B, C, D, E.
See Solution
Problem 23656
Find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
for
y
=
2
x
4
+
9
x
2
4
x
y=\frac{2 x^{4}+9 x^{2}}{4 x}
y
=
4
x
2
x
4
+
9
x
2
. Choices are A, B, C, D, E.
See Solution
Problem 23657
Which expression is NOT equal to
(
3
x
−
12
)
(
x
+
4
)
(3 x-12)(x+4)
(
3
x
−
12
)
(
x
+
4
)
?
3
(
x
2
−
8
x
+
16
)
3\left(x^{2}-8 x+16\right)
3
(
x
2
−
8
x
+
16
)
,
3
(
x
2
−
16
)
3\left(x^{2}-16\right)
3
(
x
2
−
16
)
,
3
x
2
−
48
3 x^{2}-48
3
x
2
−
48
,
3
x
(
x
+
4
)
−
12
(
x
+
4
)
3 x(x+4)-12(x+4)
3
x
(
x
+
4
)
−
12
(
x
+
4
)
See Solution
Problem 23658
Find the volume of a cylinder with
r
=
2
b
r=2b
r
=
2
b
and
h
=
5
b
+
3
h=5b+3
h
=
5
b
+
3
using
V
=
π
r
2
h
V=\pi r^{2} h
V
=
π
r
2
h
in terms of
b
b
b
.
See Solution
Problem 23659
Find the values of
y
y
y
and the gradient at
x
=
−
1
x=-1
x
=
−
1
for the function
y
=
−
4
x
3
−
x
2
+
3
x
+
1
y=-4x^3-x^2+3x+1
y
=
−
4
x
3
−
x
2
+
3
x
+
1
.
See Solution
Problem 23660
Solve for
x
x
x
in the equation:
12
x
−
30
=
−
6
12 x - 30 = -6
12
x
−
30
=
−
6
.
See Solution
Problem 23661
Solve for
x
x
x
:
3
x
+
1
=
10
3 x + 1 = 10
3
x
+
1
=
10
See Solution
Problem 23662
Solve for
t
t
t
in the equation:
8
−
3
t
=
2
8 - 3t = 2
8
−
3
t
=
2
.
See Solution
Problem 23663
Solve for
y
y
y
in the equation:
15
−
3
y
=
15
15 - 3y = 15
15
−
3
y
=
15
.
See Solution
Problem 23664
Solve for
a
a
a
in the equation
6
a
+
5
=
9
6 a + 5 = 9
6
a
+
5
=
9
.
See Solution
Problem 23665
Find the derivative of
f
(
x
)
=
3
x
+
5
4
−
x
f(x)=\frac{3x+5}{4-x}
f
(
x
)
=
4
−
x
3
x
+
5
.
See Solution
Problem 23666
Solve for c in the equation:
8
⋅
4
−
2
=
3
c
8 \cdot 4 - 2 = 3c
8
⋅
4
−
2
=
3
c
.
See Solution
Problem 23667
Calculate
(
54
÷
9
)
×
3
(54 \div 9) \times 3
(
54
÷
9
)
×
3
.
See Solution
Problem 23668
Solve for
c
c
c
in the equation:
4
−
2
=
3
c
4 - 2 = 3c
4
−
2
=
3
c
.
See Solution
Problem 23669
Solve the equation:
−
8
x
+
3
=
−
29
-8 x + 3 = -29
−
8
x
+
3
=
−
29
.
See Solution
Problem 23670
Show that the curve
y
=
2
x
2
−
3
x
+
1
y=2 x^{2}-3 x+1
y
=
2
x
2
−
3
x
+
1
and the line
y
=
k
x
+
k
2
y=k x+k^{2}
y
=
k
x
+
k
2
intersect for any constant
k
k
k
.
See Solution
Problem 23671
Calculate
(
14
−
7
)
×
(
40
−
32
)
(14-7) \times(40-32)
(
14
−
7
)
×
(
40
−
32
)
.
See Solution
Problem 23672
Calculate
1
2
×
(
12
+
8
)
\frac{1}{2} \times(12+8)
2
1
×
(
12
+
8
)
.
See Solution
Problem 23673
Solve the inequality:
6
≤
n
+
3
1
4
6 \leq n + 3 \frac{1}{4}
6
≤
n
+
3
4
1
.
See Solution
Problem 23674
Solve the equation:
y
−
7
2
y
=
5
y
\frac{y-7}{2 y}=\frac{5}{y}
2
y
y
−
7
=
y
5
.
See Solution
Problem 23675
Find the derivative of
f
(
x
)
=
(
2
x
−
x
3
)
2
−
x
2
f(x)=(2x-x^{3})\sqrt{2-x^{2}}
f
(
x
)
=
(
2
x
−
x
3
)
2
−
x
2
.
See Solution
Problem 23676
Solve the equation:
x
3
−
2
x
2
x
3
=
−
2
x
2
\frac{x^{3}-2 x^{2}}{x^{3}}=-2 x^{2}
x
3
x
3
−
2
x
2
=
−
2
x
2
.
See Solution
Problem 23677
Calculate
82
×
(
−
13
)
82 \times (-13)
82
×
(
−
13
)
.
See Solution
Problem 23678
Solve for
x
x
x
:
−
x
2
+
10
x
=
3
x
+
6
-x^{2}+10 x=3 x+6
−
x
2
+
10
x
=
3
x
+
6
See Solution
Problem 23679
Balance the equation
G
a
2
O
3
(
s
)
+
6
H
C
l
(
a
q
)
→
2
G
a
C
l
3
(
a
q
)
+
3
H
2
O
(
l
)
\mathrm{Ga}_{2} \mathrm{O}_{3}(s)+6 \mathrm{HCl}(aq) \rightarrow 2 \mathrm{GaCl}_{3}(aq)+3 \mathrm{H}_{2} \mathrm{O}(l)
Ga
2
O
3
(
s
)
+
6
HCl
(
a
q
)
→
2
GaCl
3
(
a
q
)
+
3
H
2
O
(
l
)
and perform stoichiometry calculations.
See Solution
Problem 23680
Evaluate
h
+
9
g
h + 9g
h
+
9
g
for
g
=
4
g=4
g
=
4
and
h
=
6
h=6
h
=
6
.
See Solution
Problem 23681
Find values for the function
f
(
x
)
=
6
f(x)=6
f
(
x
)
=
6
: (a)
f
(
9
)
f(9)
f
(
9
)
, (b)
f
(
−
9
)
f(-9)
f
(
−
9
)
, (c)
f
(
3.3
)
f(3.3)
f
(
3.3
)
, (d)
f
(
−
3.6
)
f(-3.6)
f
(
−
3.6
)
.
See Solution
Problem 23682
Find the value of
f
(
p
)
f(p)
f
(
p
)
for the function
f
(
x
)
=
−
8
−
x
f(x)=\sqrt{-8-x}
f
(
x
)
=
−
8
−
x
.
See Solution
Problem 23683
Find
f
(
7
)
f(7)
f
(
7
)
,
f
(
−
6
)
f(-6)
f
(
−
6
)
,
f
(
−
3.8
)
f(-3.8)
f
(
−
3.8
)
, and
f
(
−
5.4
)
f(-5.4)
f
(
−
5.4
)
for the piecewise function:
f
(
x
)
=
{
−
2
x
+
16
if
x
≤
−
4
;
3
if
−
4
<
x
<
3
;
x
+
8
if
x
≥
3
}
f(x) = \{-2x + 16 \text{ if } x \leq -4; 3 \text{ if } -4 < x < 3; x + 8 \text{ if } x \geq 3\}
f
(
x
)
=
{
−
2
x
+
16
if
x
≤
−
4
;
3
if
−
4
<
x
<
3
;
x
+
8
if
x
≥
3
}
.
See Solution
Problem 23684
Evaluate
f
(
x
)
=
x
2
−
4
f(x)=x^{2}-4
f
(
x
)
=
x
2
−
4
for (a)
f
(
3
p
)
f(3 p)
f
(
3
p
)
, (b)
f
(
−
3
q
)
f(-3 q)
f
(
−
3
q
)
, and (c)
f
(
x
+
5
)
f(x+5)
f
(
x
+
5
)
.
See Solution
Problem 23685
Find the derivative of
f
(
x
)
=
2
−
5
x
cos
10
x
f(x)=\frac{2-5 x}{\cos 10 x}
f
(
x
)
=
c
o
s
10
x
2
−
5
x
.
See Solution
Problem 23686
Find the difference quotient
f
(
x
+
h
)
−
f
(
x
)
h
\frac{f(x+h)-f(x)}{h}
h
f
(
x
+
h
)
−
f
(
x
)
for
f
(
x
)
=
9
x
+
1
f(x)=9x+1
f
(
x
)
=
9
x
+
1
and
h
≠
0
h \neq 0
h
=
0
. Simplify your answer.
See Solution
Problem 23687
Find the difference quotient
f
(
x
+
h
)
−
f
(
x
)
h
\frac{f(x+h)-f(x)}{h}
h
f
(
x
+
h
)
−
f
(
x
)
for
f
(
x
)
=
x
2
+
4
f(x)=x^{2}+4
f
(
x
)
=
x
2
+
4
where
h
≠
0
h \neq 0
h
=
0
. Simplify your answer.
See Solution
Problem 23688
Calculate the state's income tax function
h
(
x
)
h(x)
h
(
x
)
for the following incomes: (a)
h
(
1260
)
h(1260)
h
(
1260
)
, (b)
h
(
7160
)
h(7160)
h
(
7160
)
, (c)
h
(
49070
)
h(49070)
h
(
49070
)
.
See Solution
Problem 23689
Calculate the income tax
h
(
x
)
h(x)
h
(
x
)
for the following incomes: (a)
1260
1260
1260
, (b)
7160
7160
7160
, (c)
49070
49070
49070
. Round to the nearest cent.
See Solution
Problem 23690
Solve:
(
−
4
)
×
(
7
5
)
×
(
−
3
4
)
÷
(
7
15
)
(-4) \times\left(\frac{7}{5}\right) \times\left(-\frac{3}{4}\right) \div\left(\frac{7}{15}\right)
(
−
4
)
×
(
5
7
)
×
(
−
4
3
)
÷
(
15
7
)
See Solution
Problem 23691
Evaluate the expression when
c
=
6
c=6
c
=
6
and
d
=
26
d=26
d
=
26
:
d
−
30
0
d-\frac{30}{0}
d
−
0
30
.
See Solution
Problem 23692
Evaluate
d
−
30
c
d - \frac{30}{c}
d
−
c
30
for
c
=
6
c=6
c
=
6
and
d
=
26
d=26
d
=
26
.
See Solution
Problem 23693
Verify if
2
1
4
\frac{2^{1}}{4}
4
2
1
equals
7
4
\frac{7}{4}
4
7
.
See Solution
Problem 23694
Estimate the mean age of females at first child birth using
f
(
x
)
=
22
x
0.045
f(x)=22 x^{0.045}
f
(
x
)
=
22
x
0.045
for the years 2010, 2013, and 2019.
See Solution
Problem 23695
Solve for
n
n
n
in the equation
2
m
+
3
n
=
2
\frac{2}{m}+\frac{3}{n}=2
m
2
+
n
3
=
2
.
See Solution
Problem 23696
Find
y
y
y
for
y
=
1
x
y=\frac{1}{x}
y
=
x
1
when
x
x
x
is -4, -3, -2, -1, 0, 1, 2.
See Solution
Problem 23697
Find the values of
y
y
y
for
y
=
1
x
y=\frac{1}{x}
y
=
x
1
when
x
=
−
4
,
−
3
,
−
2
,
−
1
,
0
,
1
,
2
,
3
,
4
x = -4, -3, -2, -1, 0, 1, 2, 3, 4
x
=
−
4
,
−
3
,
−
2
,
−
1
,
0
,
1
,
2
,
3
,
4
.
See Solution
Problem 23698
Solve for
m
m
m
in the equation:
251
=
m
−
8
(
5
m
−
7
)
251 = m - 8(5m - 7)
251
=
m
−
8
(
5
m
−
7
)
.
See Solution
Problem 23699
Convert
8.44
×
1
0
−
3
m
8.44 \times 10^{-3} \mathrm{~m}
8.44
×
1
0
−
3
m
to millimeters (mm).
See Solution
Problem 23700
Calculate the value of
−
8
+
10
-8 + 10
−
8
+
10
.
See Solution
<
1
...
234
235
236
237
238
239
240
...
270
>
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