Math  /  Algebra

QuestionSimplify the expression (sinθcosθ)2(\sin \theta - \cos \theta)^{2}.

Studdy Solution
We know from the Pythagorean identity in trigonometry that (sinθ)2+(cosθ)2=1(\sin \theta)^{2} + (\cos \theta)^{2} =1. We can substitute this into our expression.
(sinθcosθ)2=12sinθcosθ(\sin \theta-\cos \theta)^{2} =1 -2 \sin \theta \cos \thetaSo, the simplified form of (sinθcosθ)2(\sin \theta-\cos \theta)^{2} is 12sinθcosθ1 -2 \sin \theta \cos \theta.

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