QuestionCreate a truth table for the expression .
Studdy Solution
Finally, we calculate the truth value of for each combination of and .
\begin{array}{|c|c|c|c|c|}
\hlinep & q & \sim p & q \leftrightarrow \sim p & \sim(q \leftrightarrow \sim p) \\
\hline & & F & F & \\
& F & F & & F \\
& & & & F \\
& F & & F & \\
\hline\end{array}
So, the truth table for the statement is as above.
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