Solved on Sep 19, 2023

Write a parabola equation in intercept form with xx-intercepts at -4 and -8, passing through (3,20)(-3,20).

STEP 1

Assumptions1. The x-intercepts of the parabola are -4 and -8. . The parabola passes through the point (-3,20).
3. The general form of a parabola in intercept form is y=a(xh)(xk)y=a(x-h)(x-k), where h and k are the x-intercepts.

STEP 2

First, we need to write the general form of the parabola using the given x-intercepts.y=a(x+4)(x+8)y=a(x+4)(x+8)

STEP 3

We know that the parabola passes through the point (-3,20). We can substitute these values into the equation to solve for a.
20=a(3+)(3+8)20=a(-3+)(-3+8)

STEP 4

implify the equation.
20=a(1)()20=a(1)()

STEP 5

olve for a.
a=20/5a=20/5

STEP 6

Calculate the value of a.
a=4a=4

STEP 7

Now that we have the value of a, we can write the final equation of the parabola.
y=4(x+4)(x+)y=4(x+4)(x+)The equation of the parabola in intercept form is y=4(x+4)(x+)y=4(x+4)(x+).

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