Find unit rates for distances, time, and quantities given in fractions.
a) 202.5 miles in 15 hours
b) 85 feet in 20 seconds
c) 42 books for 12 students
d) 65 children from 13 families
STEP 1
Assumptions1. The rates are given as follows a)202.5 miles in15 hours b)85 feet in20 seconds c)42 books for12 students d)65 children from13 families. The unit rate is the rate for one unit of the second quantity in the rate.
STEP 2
First, we need to write each rate as a fraction.a) The rate is202.5 miles in15 hours, so the fraction is15hours202.5milesb) The rate is85 feet in20 seconds, so the fraction is20seconds85feetc) The rate is42 books for12 students, so the fraction is12students42booksd) The rate is65 children from13 families, so the fraction is13families65children
STEP 3
Now, we need to find the unit rate for each fraction. The unit rate is the rate when the denominator is1.a) For202.5 miles in15 hours, the unit rate is15hours202.5miles=15hours/15202.5miles/15=1hour13.5milesb) For85 feet in20 seconds, the unit rate is20seconds85feet=20seconds/2085feet/20=1second.25feetc) For42 books for12 students, the unit rate is12students42books=12students/1242books/12=1student3.5booksd) For65 children from13 families, the unit rate is13families65children=13families/1365children/13=1family5childrenThe unit rates are13.5 miles per hour,.25 feet per second,3.5 books per student, and5 children per family.
