Solved on Dec 20, 2023

Find an equation with solution $n=5$ using multiplication. Select all correct answers.
$4=\frac{20}{n}$ $2(n+1)=10$ $36=8 n$ $7 n=28$ $4=4 n$ $36=9 n$

STEP 1

Assumptions
1. We are looking for an equation that has a solution of $n=4$ .
2. We will use multiplication in the equation.
3. The variable to be used in the equation is $n$ .

STEP 2

We will test each given equation by substituting $n=4$ and checking if the equation holds true.

STEP 3

Test the first equation:
$4 = \frac{20}{n}$
Substitute $n=4$ :
$4 = \frac{20}{4}$

STEP 4

Calculate the right-hand side:
$4 = \frac{20}{4} = 5$
Since $4 \neq 5$ , the first equation does not have a solution of $n=4$ .

STEP 5

Test the second equation:
$2(n+1) = 10$
Substitute $n=4$ :
$2(4+1) = 10$

STEP 6

Calculate the left-hand side:
$2(4+1) = 2 \cdot 5 = 10$
Since $10 = 10$ , the second equation has a solution of $n=4$ .

STEP 7

Test the third equation:
$36 = 8n$
Substitute $n=4$ :
$36 = 8 \cdot 4$

STEP 8

Calculate the right-hand side:
$36 = 8 \cdot 4 = 32$
Since $36 \neq 32$ , the third equation does not have a solution of $n=4$ .

STEP 9

Test the fourth equation:
$7n = 28$
Substitute $n=4$ :
$7 \cdot 4 = 28$

STEP 10

Calculate the left-hand side:
$7 \cdot 4 = 28$
Since $28 = 28$ , the fourth equation has a solution of $n=4$ .

STEP 11

Test the fifth equation:
$4 = 4n$
Substitute $n=4$ :
$4 = 4 \cdot 4$

STEP 12

Calculate the right-hand side:
$4 = 4 \cdot 4 = 16$
Since $4 \neq 16$ , the fifth equation does not have a solution of $n=4$ .

STEP 13

Test the sixth equation:
$36 = 9n$
Substitute $n=4$ :
$36 = 9 \cdot 4$

STEP 14

Calculate the right-hand side:
$36 = 9 \cdot 4 = 36$
Since $36 = 36$ , the sixth equation has a solution of $n=4$ .

STEP 15

The correct equations that have a solution of $n=4$ are:
$2(n+1) = 10$ $7n = 28$ $36 = 9n$

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Find an equation with solution $n=5$ using multiplication. Select all correct answers.
$4=\frac{20}{n}$ $2(n+1)=10$ $36=8 n$ $7 n=28$ $4=4 n$ $36=9 n$

STEP 1

Assumptions
1. We are looking for an equation that has a solution of $n=4$ .
2. We will use multiplication in the equation.
3. The variable to be used in the equation is $n$ .

STEP 2

We will test each given equation by substituting $n=4$ and checking if the equation holds true.

STEP 3

Test the first equation:
$4 = \frac{20}{n}$
Substitute $n=4$ :
$4 = \frac{20}{4}$

STEP 4

Calculate the right-hand side:
$4 = \frac{20}{4} = 5$
Since $4 \neq 5$ , the first equation does not have a solution of $n=4$ .

STEP 5

Test the second equation:
$2(n+1) = 10$
Substitute $n=4$ :
$2(4+1) = 10$

STEP 6

Calculate the left-hand side:
$2(4+1) = 2 \cdot 5 = 10$
Since $10 = 10$ , the second equation has a solution of $n=4$ .

STEP 7

Test the third equation:
$36 = 8n$
Substitute $n=4$ :
$36 = 8 \cdot 4$

STEP 8

Calculate the right-hand side:
$36 = 8 \cdot 4 = 32$
Since $36 \neq 32$ , the third equation does not have a solution of $n=4$ .

STEP 9

Test the fourth equation:
$7n = 28$
Substitute $n=4$ :
$7 \cdot 4 = 28$

STEP 10

Calculate the left-hand side:
$7 \cdot 4 = 28$
Since $28 = 28$ , the fourth equation has a solution of $n=4$ .

STEP 11

Test the fifth equation:
$4 = 4n$
Substitute $n=4$ :
$4 = 4 \cdot 4$

STEP 12

Calculate the right-hand side:
$4 = 4 \cdot 4 = 16$
Since $4 \neq 16$ , the fifth equation does not have a solution of $n=4$ .

STEP 13

Test the sixth equation:
$36 = 9n$
Substitute $n=4$ :
$36 = 9 \cdot 4$

STEP 14

Calculate the right-hand side:
$36 = 9 \cdot 4 = 36$
Since $36 = 36$ , the sixth equation has a solution of $n=4$ .

STEP 15

The correct equations that have a solution of $n=4$ are:
$2(n+1) = 10$ $7n = 28$ $36 = 9n$

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Find an equation with solution n=5n=5n=5 using multiplication. Select all correct answers.4=20n4=\frac{20}{n}4=n20​ 2(n+1)=102(n+1)=102(n+1)=10 36=8n36=8 n36=8n 7n=287 n=287n=28 4=4n4=4 n4=4n 36=9n36=9 n36=9n

STEP 1

Assumptions1. We are looking for an equation that has a solution of n=4n=4n=4.2. We will use multiplication in the equation.3. The variable to be used in the equation is nnn.

STEP 2

We will test each given equation by substituting n=4n=4n=4 and checking if the equation holds true.

STEP 3

Test the first equation:4=20n4 = \frac{20}{n}4=n20​Substitute n=4n=4n=4:4=2044 = \frac{20}{4}4=420​

STEP 4

Calculate the right-hand side:4=204=54 = \frac{20}{4} = 54=420​=5Since 4≠54 \neq 54=5, the first equation does not have a solution of n=4n=4n=4.

STEP 5

Test the second equation:2(n+1)=102(n+1) = 102(n+1)=10Substitute n=4n=4n=4:2(4+1)=102(4+1) = 102(4+1)=10

STEP 6

Calculate the left-hand side:2(4+1)=2⋅5=102(4+1) = 2 \cdot 5 = 102(4+1)=2⋅5=10Since 10=1010 = 1010=10, the second equation has a solution of n=4n=4n=4.

STEP 7

Test the third equation:36=8n36 = 8n36=8nSubstitute n=4n=4n=4:36=8⋅436 = 8 \cdot 436=8⋅4

STEP 8

Calculate the right-hand side:36=8⋅4=3236 = 8 \cdot 4 = 3236=8⋅4=32Since 36≠3236 \neq 3236=32, the third equation does not have a solution of n=4n=4n=4.

STEP 9

Test the fourth equation:7n=287n = 287n=28Substitute n=4n=4n=4:7⋅4=287 \cdot 4 = 287⋅4=28

STEP 10

Calculate the left-hand side:7⋅4=287 \cdot 4 = 287⋅4=28Since 28=2828 = 2828=28, the fourth equation has a solution of n=4n=4n=4.

STEP 11

Test the fifth equation:4=4n4 = 4n4=4nSubstitute n=4n=4n=4:4=4⋅44 = 4 \cdot 44=4⋅4

STEP 12

Calculate the right-hand side:4=4⋅4=164 = 4 \cdot 4 = 164=4⋅4=16Since 4≠164 \neq 164=16, the fifth equation does not have a solution of n=4n=4n=4.

STEP 13

Test the sixth equation:36=9n36 = 9n36=9nSubstitute n=4n=4n=4:36=9⋅436 = 9 \cdot 436=9⋅4

STEP 14

Calculate the right-hand side:36=9⋅4=3636 = 9 \cdot 4 = 3636=9⋅4=36Since 36=3636 = 3636=36, the sixth equation has a solution of n=4n=4n=4.

STEP 15

The correct equations that have a solution of n=4n=4n=4 are:2(n+1)=102(n+1) = 102(n+1)=10 7n=287n = 287n=28 36=9n36 = 9n36=9n

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Find an equation with solution $n=5$ using multiplication. Select all correct answers.
$4=\frac{20}{n}$ $2(n+1)=10$ $36=8 n$ $7 n=28$ $4=4 n$ $36=9 n$

Assumptions
1. We are looking for an equation that has a solution of $n=4$ .
2. We will use multiplication in the equation.
3. The variable to be used in the equation is $n$ .

We will test each given equation by substituting $n=4$ and checking if the equation holds true.

Test the first equation:
$4 = \frac{20}{n}$
Substitute $n=4$ :
$4 = \frac{20}{4}$

Calculate the right-hand side:
$4 = \frac{20}{4} = 5$
Since $4 \neq 5$ , the first equation does not have a solution of $n=4$ .

Test the second equation:
$2(n+1) = 10$
Substitute $n=4$ :
$2(4+1) = 10$

Calculate the left-hand side:
$2(4+1) = 2 \cdot 5 = 10$
Since $10 = 10$ , the second equation has a solution of $n=4$ .

Test the third equation:
$36 = 8n$
Substitute $n=4$ :
$36 = 8 \cdot 4$

Calculate the right-hand side:
$36 = 8 \cdot 4 = 32$
Since $36 \neq 32$ , the third equation does not have a solution of $n=4$ .

Test the fourth equation:
$7n = 28$
Substitute $n=4$ :
$7 \cdot 4 = 28$

Calculate the left-hand side:
$7 \cdot 4 = 28$
Since $28 = 28$ , the fourth equation has a solution of $n=4$ .

Test the fifth equation:
$4 = 4n$
Substitute $n=4$ :
$4 = 4 \cdot 4$

Calculate the right-hand side:
$4 = 4 \cdot 4 = 16$
Since $4 \neq 16$ , the fifth equation does not have a solution of $n=4$ .

Test the sixth equation:
$36 = 9n$
Substitute $n=4$ :
$36 = 9 \cdot 4$

Calculate the right-hand side:
$36 = 9 \cdot 4 = 36$
Since $36 = 36$ , the sixth equation has a solution of $n=4$ .

The correct equations that have a solution of $n=4$ are:
$2(n+1) = 10$ $7n = 28$ $36 = 9n$