Solved on Mar 01, 2024

Find the value(s) of zz that satisfy the equation 3=z+433=\frac{z+4}{3}.

STEP 1

Assumptions
1. We are given the equation z+43=3 \frac{z+4}{3} = 3 .
2. We need to solve for the variable z z .
3. The possible solutions provided are z=7 z = -7 and z=5 z = 5 .

STEP 2

To solve for z z , we need to isolate z z on one side of the equation. We can start by multiplying both sides of the equation by 3 to eliminate the denominator.
3×z+43=3×3 3 \times \frac{z+4}{3} = 3 \times 3

STEP 3

Now simplify both sides of the equation.
z+4=9 z + 4 = 9

STEP 4

Next, we subtract 4 from both sides of the equation to solve for z z .
z+44=94 z + 4 - 4 = 9 - 4

STEP 5

Simplify the equation to find the value of z z .
z=5 z = 5
The value of z z that satisfies the equation is z=5 z = 5 .

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