Solved on Dec 14, 2023

Find the value of xx that makes 48473x4 \mid 8473x true, where \mid represents divisibility.

STEP 1

Assumptions
1. We are looking for a digit xx such that 8473x8473x is divisible by 44.
2. A number is divisible by 44 if the number formed by its last two digits is divisible by 44.

STEP 2

Since we are only concerned with the divisibility of 8473x8473x by 44, we need to focus on the last two digits of the number, which are 3x3x.

STEP 3

The divisibility rule for 44 states that if the last two digits of a number form a number that is divisible by 44, then the entire number is divisible by 44.

STEP 4

We need to find a digit xx such that the two-digit number 3x3x is divisible by 44.

STEP 5

List all two-digit multiples of 44 that start with 33 to find the possible values of xx.

STEP 6

The two-digit multiples of 44 that start with 33 are 3232, 3636, and 4040 (note that 4040 is not considered since it is not a two-digit number with 33 as the tens place).

STEP 7

From the multiples listed in STEP_6, we can see that the possible values for xx are 22 and 66.

STEP 8

Therefore, the values of xx that make 8473x8473x divisible by 44 are 22 and 66.
The value of xx for the last digits that makes 48473x4 \mid 8473x a true statement can be either 22 or 66.

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