Fractions and Decimals

Discrete Mathematics

Differential Equations

Solved on Nov 09, 2023

Find the value of $3 \sqrt[3]{x+y}-\sqrt{x}$ when $x=4$ and $y=-12$ .

STEP 1

Assumptions1. The value of $x$ is4. . The value of $y$ is -12.
3. We are asked to find the value of the expression $3 \sqrt[3]{x+y}-\sqrt{x}$ .

STEP 2

First, we need to substitute the given values of $x$ and $y$ into the expression.
$\sqrt[]{x+y}-\sqrt{x} = \sqrt[]{4+(-12)}-\sqrt{4}$

STEP 3

Now, simplify the expression inside the cube root.
$3 \sqrt[3]{+(-12)}-\sqrt{} =3 \sqrt[3]{-8}-\sqrt{}$

STEP 4

Calculate the cube root of -8 and the square root of4.
$3 \sqrt[3]{-8}-\sqrt{4} =3 \times -2 -2$

STEP 5

Now, simplify the expression.
$3 \times -2 -2 = - -2$

STEP 6

Finally, calculate the value of the expression.
$-6 -2 = -8$ So, the value of the expression when $x=4$ and $y=-12$ is -8.

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