Solved on Jan 31, 2024

Find the value of 23=82^3 = 8.

STEP 1

Assumptions
1. We need to evaluate the expression 223\frac{2}{2^{-3}}.

STEP 2

Understand the properties of exponents. Specifically, we will use the property that an=1ana^{-n} = \frac{1}{a^n}, where aa is a nonzero real number and nn is a positive integer.

STEP 3

Apply the property of exponents to rewrite the denominator of the given expression.
23=1232^{-3} = \frac{1}{2^3}

STEP 4

Now, rewrite the original expression using the result from STEP_3.
223=2123\frac{2}{2^{-3}} = \frac{2}{\frac{1}{2^3}}

STEP 5

Recognize that dividing by a fraction is the same as multiplying by its reciprocal.
2123=2×23\frac{2}{\frac{1}{2^3}} = 2 \times 2^3

STEP 6

Now, apply the property of exponents that states am×an=am+na^m \times a^n = a^{m+n}, where aa is a nonzero real number and mm and nn are integers.

STEP 7

Since the base is the same (2), add the exponents.
2×23=21×23=21+32 \times 2^3 = 2^1 \times 2^3 = 2^{1+3}

STEP 8

Simplify the exponent.
21+3=242^{1+3} = 2^4

STEP 9

Calculate the value of 242^4.
24=2×2×2×2=162^4 = 2 \times 2 \times 2 \times 2 = 16
The value of 223\frac{2}{2^{-3}} is 16.

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