Solved on Jan 10, 2024

Find the quotient of $2,356 \div 27$ .

STEP 1

Assumptions
1. We are performing a division operation.
2. The dividend is $2,356.<br />3. The divisor is$ 27.

STEP 2

To divide $2,356 by$ 27, we will use long division.

STEP 3

First, we determine how many times $27 goes into the first digit of$ 2,356, which is $2. Since$ 27 is greater than $2, we cannot divide$ 2 by $27. Therefore, we consider the first two digits of the dividend, which is$ 23.

STEP 4

Now, we determine how many times $27 goes into$ 23. Since $27 is greater than$ 23, we cannot divide $23 by$ 27 either. Therefore, we consider the first three digits of the dividend, which is $235.

STEP 5

We find the largest multiple of $27 that is less than or equal to$ 235. This is done by estimating how many times $27 fits into$ 235 without going over.

STEP 6

Since $27 \times 8 = 216$ and $27 \times 9 = 243$ , which is greater than $235$ , we know that $27$ goes into $235$ a maximum of $8$ times.

STEP 7

We write the $8$ above the third digit of the dividend, indicating that $27$ goes into $235$ eight times.

STEP 8

Now we multiply $27$ by $8$ to find the product.
$27 \times 8 = 216$

STEP 9

We subtract $216$ from $235$ to find the remainder of this part of the division.
$235 - 216 = 19$

STEP 10

We bring down the next digit of the dividend, which is $6$ , to the right of the remainder $19$ , making it $196$ .

STEP 11

We now determine how many times $27$ goes into $196$ .

STEP 12

Since $27 \times 7 = 189$ and $27 \times 8 = 216$ , which is greater than $196$ , we know that $27$ goes into $196$ a maximum of $7$ times.

STEP 13

We write the $7$ above the last digit of the dividend, indicating that $27$ goes into $196$ seven times.

STEP 14

We multiply $27$ by $7$ to find the product.
$27 \times 7 = 189$

STEP 15

We subtract $189$ from $196$ to find the remainder of the division.
$196 - 189 = 7$

STEP 16

Since there are no more digits to bring down, we have completed the long division process. The quotient is the number above the dividend, and the remainder is the result of the last subtraction.

STEP 17

The quotient of the division $2,356 \div 27$ is $87$ with a remainder of $7$ .
The solution is $87$ remainder $7$ .

Was this helpful?

Find the quotient of $2,356 \div 27$ .

STEP 1

Assumptions
1. We are performing a division operation.
2. The dividend is $2,356.<br />3. The divisor is$ 27.

STEP 2

To divide $2,356 by$ 27, we will use long division.

STEP 3

First, we determine how many times $27 goes into the first digit of$ 2,356, which is $2. Since$ 27 is greater than $2, we cannot divide$ 2 by $27. Therefore, we consider the first two digits of the dividend, which is$ 23.

STEP 4

Now, we determine how many times $27 goes into$ 23. Since $27 is greater than$ 23, we cannot divide $23 by$ 27 either. Therefore, we consider the first three digits of the dividend, which is $235.

STEP 5

We find the largest multiple of $27 that is less than or equal to$ 235. This is done by estimating how many times $27 fits into$ 235 without going over.

STEP 6

Since $27 \times 8 = 216$ and $27 \times 9 = 243$ , which is greater than $235$ , we know that $27$ goes into $235$ a maximum of $8$ times.

STEP 7

We write the $8$ above the third digit of the dividend, indicating that $27$ goes into $235$ eight times.

STEP 8

Now we multiply $27$ by $8$ to find the product.
$27 \times 8 = 216$

STEP 9

We subtract $216$ from $235$ to find the remainder of this part of the division.
$235 - 216 = 19$

STEP 10

We bring down the next digit of the dividend, which is $6$ , to the right of the remainder $19$ , making it $196$ .

STEP 11

We now determine how many times $27$ goes into $196$ .

STEP 12

Since $27 \times 7 = 189$ and $27 \times 8 = 216$ , which is greater than $196$ , we know that $27$ goes into $196$ a maximum of $7$ times.

STEP 13

We write the $7$ above the last digit of the dividend, indicating that $27$ goes into $196$ seven times.

STEP 14

We multiply $27$ by $7$ to find the product.
$27 \times 7 = 189$

STEP 15

We subtract $189$ from $196$ to find the remainder of the division.
$196 - 189 = 7$

STEP 16

Since there are no more digits to bring down, we have completed the long division process. The quotient is the number above the dividend, and the remainder is the result of the last subtraction.

STEP 17

The quotient of the division $2,356 \div 27$ is $87$ with a remainder of $7$ .
The solution is $87$ remainder $7$ .

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Find the quotient of 2,356÷272,356 \div 272,356÷27.

STEP 1

Assumptions1. We are performing a division operation.2. The dividend is 2,356.<br/>3.Thedivisoris2,356.<br />3. The divisor is 2,356.<br/>3.Thedivisoris27.

STEP 2

To divide 2,356by2,356 by 2,356by27, we will use long division.

STEP 3

STEP 4

Now, we determine how many times 27goesinto27 goes into 27goesinto23. Since 27isgreaterthan27 is greater than 27isgreaterthan23, we cannot divide 23by23 by 23by27 either. Therefore, we consider the first three digits of the dividend, which is $235.

STEP 5

We find the largest multiple of 27thatislessthanorequalto27 that is less than or equal to 27thatislessthanorequalto235. This is done by estimating how many times 27fitsinto27 fits into 27fitsinto235 without going over.

STEP 6

Since 27×8=21627 \times 8 = 21627×8=216 and 27×9=24327 \times 9 = 24327×9=243, which is greater than 235235235, we know that 272727 goes into 235235235 a maximum of 888 times.

STEP 7

We write the 888 above the third digit of the dividend, indicating that 272727 goes into 235235235 eight times.

STEP 8

Now we multiply 272727 by 888 to find the product.27×8=21627 \times 8 = 21627×8=216

STEP 9

We subtract 216216216 from 235235235 to find the remainder of this part of the division.235−216=19235 - 216 = 19235−216=19

STEP 10

We bring down the next digit of the dividend, which is 666, to the right of the remainder 191919, making it 196196196.

STEP 11

We now determine how many times 272727 goes into 196196196.

STEP 12

Since 27×7=18927 \times 7 = 18927×7=189 and 27×8=21627 \times 8 = 21627×8=216, which is greater than 196196196, we know that 272727 goes into 196196196 a maximum of 777 times.

STEP 13

We write the 777 above the last digit of the dividend, indicating that 272727 goes into 196196196 seven times.

STEP 14

We multiply 272727 by 777 to find the product.27×7=18927 \times 7 = 18927×7=189

STEP 15

We subtract 189189189 from 196196196 to find the remainder of the division.196−189=7196 - 189 = 7196−189=7

STEP 16

Since there are no more digits to bring down, we have completed the long division process. The quotient is the number above the dividend, and the remainder is the result of the last subtraction.

STEP 17

The quotient of the division 2,356÷272,356 \div 272,356÷27 is 878787 with a remainder of 777.The solution is 878787 remainder 777.

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Find the quotient of $2,356 \div 27$ .

Assumptions
1. We are performing a division operation.
2. The dividend is $2,356.<br />3. The divisor is$ 27.

To divide $2,356 by$ 27, we will use long division.

Now, we determine how many times $27 goes into$ 23. Since $27 is greater than$ 23, we cannot divide $23 by$ 27 either. Therefore, we consider the first three digits of the dividend, which is $235.

We find the largest multiple of $27 that is less than or equal to$ 235. This is done by estimating how many times $27 fits into$ 235 without going over.

Since $27 \times 8 = 216$ and $27 \times 9 = 243$ , which is greater than $235$ , we know that $27$ goes into $235$ a maximum of $8$ times.

We write the $8$ above the third digit of the dividend, indicating that $27$ goes into $235$ eight times.

Now we multiply $27$ by $8$ to find the product.
$27 \times 8 = 216$

We subtract $216$ from $235$ to find the remainder of this part of the division.
$235 - 216 = 19$

We bring down the next digit of the dividend, which is $6$ , to the right of the remainder $19$ , making it $196$ .

We now determine how many times $27$ goes into $196$ .

Since $27 \times 7 = 189$ and $27 \times 8 = 216$ , which is greater than $196$ , we know that $27$ goes into $196$ a maximum of $7$ times.

We write the $7$ above the last digit of the dividend, indicating that $27$ goes into $196$ seven times.

We multiply $27$ by $7$ to find the product.
$27 \times 7 = 189$

We subtract $189$ from $196$ to find the remainder of the division.
$196 - 189 = 7$

The quotient of the division $2,356 \div 27$ is $87$ with a remainder of $7$ .
The solution is $87$ remainder $7$ .