Solved on Jan 20, 2024

Verify that $(6+4)+y=6+(4+y)$ is true when $y=5$ by substituting and simplifying both sides.

STEP 1

Assumptions
1. We are given the equation $(6+4)+y=6+(4+y)$ .
2. We need to show that the equation is true for $y=5$ .

STEP 2

First, we will substitute $y=5$ into the left-hand side (LHS) of the equation.
$LHS = (6+4)+y$

STEP 3

Now, plug in the value of $y$ .
$LHS = (6+4)+5$

STEP 4

Simplify the expression by adding the numbers inside the parentheses.
$LHS = 10+5$

STEP 5

Now, add the remaining numbers.
$LHS = 15$

STEP 6

Next, we will substitute $y=5$ into the right-hand side (RHS) of the equation.
$RHS = 6+(4+y)$

STEP 7

Now, plug in the value of $y$ .
$RHS = 6+(4+5)$

STEP 8

Simplify the expression by adding the numbers inside the parentheses.
$RHS = 6+9$

STEP 9

Now, add the remaining numbers.
$RHS = 15$

STEP 10

Finally, we compare the LHS and RHS to see if they are equal.
$LHS = RHS$

STEP 11

Since both LHS and RHS are equal to 15, we can conclude that the given equation is true for $y=5$ .
$15 = 15$
The equation $(6+4)+y=6+(4+y)$ is indeed true for the value $y=5$ .

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Verify that $(6+4)+y=6+(4+y)$ is true when $y=5$ by substituting and simplifying both sides.

STEP 1

Assumptions
1. We are given the equation $(6+4)+y=6+(4+y)$ .
2. We need to show that the equation is true for $y=5$ .

STEP 2

First, we will substitute $y=5$ into the left-hand side (LHS) of the equation.
$LHS = (6+4)+y$

STEP 3

Now, plug in the value of $y$ .
$LHS = (6+4)+5$

STEP 4

Simplify the expression by adding the numbers inside the parentheses.
$LHS = 10+5$

STEP 5

Now, add the remaining numbers.
$LHS = 15$

STEP 6

Next, we will substitute $y=5$ into the right-hand side (RHS) of the equation.
$RHS = 6+(4+y)$

STEP 7

Now, plug in the value of $y$ .
$RHS = 6+(4+5)$

STEP 8

Simplify the expression by adding the numbers inside the parentheses.
$RHS = 6+9$

STEP 9

Now, add the remaining numbers.
$RHS = 15$

STEP 10

Finally, we compare the LHS and RHS to see if they are equal.
$LHS = RHS$

STEP 11

Since both LHS and RHS are equal to 15, we can conclude that the given equation is true for $y=5$ .
$15 = 15$
The equation $(6+4)+y=6+(4+y)$ is indeed true for the value $y=5$ .

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Verify that (6+4)+y=6+(4+y)(6+4)+y=6+(4+y)(6+4)+y=6+(4+y) is true when y=5y=5y=5 by substituting and simplifying both sides.

STEP 1

Assumptions1. We are given the equation (6+4)+y=6+(4+y)(6+4)+y=6+(4+y)(6+4)+y=6+(4+y).2. We need to show that the equation is true for y=5y=5y=5.

STEP 2

First, we will substitute y=5y=5y=5 into the left-hand side (LHS) of the equation.LHS=(6+4)+yLHS = (6+4)+yLHS=(6+4)+y

STEP 3

Now, plug in the value of yyy.LHS=(6+4)+5LHS = (6+4)+5LHS=(6+4)+5

STEP 4

Simplify the expression by adding the numbers inside the parentheses.LHS=10+5LHS = 10+5LHS=10+5

STEP 5

Now, add the remaining numbers.LHS=15LHS = 15LHS=15

STEP 6

Next, we will substitute y=5y=5y=5 into the right-hand side (RHS) of the equation.RHS=6+(4+y)RHS = 6+(4+y)RHS=6+(4+y)

STEP 7

Now, plug in the value of yyy.RHS=6+(4+5)RHS = 6+(4+5)RHS=6+(4+5)

STEP 8

Simplify the expression by adding the numbers inside the parentheses.RHS=6+9RHS = 6+9RHS=6+9

STEP 9

Now, add the remaining numbers.RHS=15RHS = 15RHS=15

STEP 10

Finally, we compare the LHS and RHS to see if they are equal.LHS=RHSLHS = RHSLHS=RHS

STEP 11

Since both LHS and RHS are equal to 15, we can conclude that the given equation is true for y=5y=5y=5.15=1515 = 1515=15The equation (6+4)+y=6+(4+y)(6+4)+y=6+(4+y)(6+4)+y=6+(4+y) is indeed true for the value y=5y=5y=5.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Verify that $(6+4)+y=6+(4+y)$ is true when $y=5$ by substituting and simplifying both sides.

Assumptions
1. We are given the equation $(6+4)+y=6+(4+y)$ .
2. We need to show that the equation is true for $y=5$ .

First, we will substitute $y=5$ into the left-hand side (LHS) of the equation.
$LHS = (6+4)+y$

Now, plug in the value of $y$ .
$LHS = (6+4)+5$

Simplify the expression by adding the numbers inside the parentheses.
$LHS = 10+5$

Now, add the remaining numbers.
$LHS = 15$

Next, we will substitute $y=5$ into the right-hand side (RHS) of the equation.
$RHS = 6+(4+y)$

Now, plug in the value of $y$ .
$RHS = 6+(4+5)$

Simplify the expression by adding the numbers inside the parentheses.
$RHS = 6+9$

Now, add the remaining numbers.
$RHS = 15$

Finally, we compare the LHS and RHS to see if they are equal.
$LHS = RHS$

Since both LHS and RHS are equal to 15, we can conclude that the given equation is true for $y=5$ .
$15 = 15$
The equation $(6+4)+y=6+(4+y)$ is indeed true for the value $y=5$ .