Solved on Dec 06, 2023

Use sum/diff identities to find the value of sin125cos55+cos125sin55\sin 125^{\circ} \cos 55^{\circ} + \cos 125^{\circ} \sin 55^{\circ}. If undefined, write DNE.

STEP 1

Assumptions
1. We are working with angles in degrees.
2. We will use the sum and difference identities for sine and cosine.
3. The sum identity for sine is sin(α+β)=sinαcosβ+cosαsinβ\sin(\alpha + \beta) = \sin \alpha \cos \beta + \cos \alpha \sin \beta.
4. The difference identity for cosine is cos(αβ)=cosαcosβ+sinαsinβ\cos(\alpha - \beta) = \cos \alpha \cos \beta + \sin \alpha \sin \beta.
5. We are looking for the exact value of the expression.

STEP 2

Recognize that the given expression resembles the sum identity for sine.
sin(α+β)=sinαcosβ+cosαsinβ\sin(\alpha + \beta) = \sin \alpha \cos \beta + \cos \alpha \sin \beta

STEP 3

Identify the angles α\alpha and β\beta that will allow us to use the sum identity to simplify the expression.
Let α=125\alpha = 125^{\circ} and β=55\beta = 55^{\circ}.

STEP 4

Apply the sum identity for sine to the expression using the identified angles.
sin125cos55+cos125sin55=sin(125+55)\sin 125^{\circ} \cos 55^{\circ} + \cos 125^{\circ} \sin 55^{\circ} = \sin(125^{\circ} + 55^{\circ})

STEP 5

Calculate the sum of the angles.
125+55=180125^{\circ} + 55^{\circ} = 180^{\circ}

STEP 6

Substitute the sum of the angles into the sine function.
sin(125+55)=sin180\sin(125^{\circ} + 55^{\circ}) = \sin 180^{\circ}

STEP 7

Evaluate the sine of 180180^{\circ}.
sin180=0\sin 180^{\circ} = 0

STEP 8

Conclude that the exact value of the original expression is 0.
The exact value of the expression sin125cos55+cos125sin55\sin 125^{\circ} \cos 55^{\circ} + \cos 125^{\circ} \sin 55^{\circ} is 0.

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