Solved on Dec 15, 2023

Given congruent triangles ABCDEF\triangle ABC \cong \triangle DEF with AB=4x5AB=4x-5, DE=67DE=67, C=5y+7\angle C=5y+7, and F=57\angle F=57, find xx and yy.

STEP 1

Assumptions
1. ABCDEF\triangle ABC \cong \triangle DEF implies that corresponding sides and angles are equal.
2. AB=4x5AB = 4x - 5 corresponds to DE=67DE = 67.
3. mC=5y+7m\angle C = 5y + 7 corresponds to mF=57m\angle F = 57.
4. We need to find the values of xx and yy.

STEP 2

Since the triangles are congruent, corresponding sides are equal. Therefore, we can set the expression for ABAB equal to DEDE.
AB=DEAB = DE

STEP 3

Substitute the given expressions for ABAB and DEDE.
4x5=674x - 5 = 67

STEP 4

Solve for xx by adding 5 to both sides of the equation.
4x5+5=67+54x - 5 + 5 = 67 + 5

STEP 5

Simplify the equation.
4x=724x = 72

STEP 6

Divide both sides by 4 to isolate xx.
4x4=724\frac{4x}{4} = \frac{72}{4}

STEP 7

Calculate the value of xx.
x=18x = 18

STEP 8

Since the triangles are congruent, corresponding angles are equal. Therefore, we can set the expression for mCm\angle C equal to mFm\angle F.
mC=mFm\angle C = m\angle F

STEP 9

Substitute the given expressions for mCm\angle C and mFm\angle F.
5y+7=575y + 7 = 57

STEP 10

Solve for yy by subtracting 7 from both sides of the equation.
5y+77=5775y + 7 - 7 = 57 - 7

STEP 11

Simplify the equation.
5y=505y = 50

STEP 12

Divide both sides by 5 to isolate yy.
5y5=505\frac{5y}{5} = \frac{50}{5}

STEP 13

Calculate the value of yy.
y=10y = 10
The values of xx and yy are x=18x = 18 and y=10y = 10.

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