Solved on Jan 07, 2024

Eliminate x-terms in system: 3x+5y=53x+5y=5, multiply by ? on both sides; 2x8y=6-2x-8y=-6, multiply by ? on both sides.

STEP 1

Assumptions
1. We have two linear equations: - 3x+5y=53x + 5y = 5 - 2x8y=6-2x - 8y = -6
2. We want to eliminate the xx-terms from the system of equations.
3. To eliminate the xx-terms, we need to find multipliers for each equation such that the coefficients of xx in both equations become additive inverses of each other.

STEP 2

Let's denote the multipliers for the first and second equations as m1m_1 and m2m_2, respectively.

STEP 3

The goal is to make the coefficients of xx in both equations equal in magnitude but opposite in sign. This means we need to find m1m_1 and m2m_2 such that:
m13x=m2(2x)m_1 \cdot 3x = -m_2 \cdot (-2x)

STEP 4

Solve the equation for m1m_1 and m2m_2:
m13=m22m_1 \cdot 3 = m_2 \cdot 2

STEP 5

We can choose the smallest positive integers for m1m_1 and m2m_2 that satisfy the equation. To do this, we can set m1m_1 equal to 2 and m2m_2 equal to 3, as these are the smallest integers that make the equation true:
m1=2,m2=3m_1 = 2, \quad m_2 = 3

STEP 6

Now, multiply the first equation by m1m_1 and the second equation by m2m_2:
First equation: 3x+5y=53x + 5y = 5 multiplied by 2 becomes 6x+10y=106x + 10y = 10.
Second equation: 2x8y=6-2x - 8y = -6 multiplied by 3 becomes 6x24y=18-6x - 24y = -18.

STEP 7

The new system of equations after applying the multipliers is:
6x+10y=106x + 10y = 10 6x24y=18-6x - 24y = -18

STEP 8

Adding these two equations together will eliminate the xx-terms:
(6x+10y)+(6x24y)=10+(18)(6x + 10y) + (-6x - 24y) = 10 + (-18)

STEP 9

Perform the addition:
6x6x+10y24y=10186x - 6x + 10y - 24y = 10 - 18

STEP 10

Simplify the equation:
0x14y=80x - 14y = -8

STEP 11

The xx-terms have been successfully eliminated, leaving us with the equation:
14y=8-14y = -8
To summarize, to eliminate the xx-terms in the given system, we should multiply the first equation by 2 and the second equation by 3.

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