Solved on Dec 01, 2023

Find the number of solutions to the linear equation 6h=h+42h-6-h=-h+4-2h.

STEP 1

Assumptions
1. The equation given is 6h=h+42h-6-h=-h+4-2h

STEP 2

First, we should simplify the equation by combining like terms on both sides. On the right side of the equation, we can combine the h-h and 2h-2h terms.
6h=3h+4-6-h=-3h+4

STEP 3

Next, we can isolate the variable hh on one side of the equation. To do this, we can add 3h3h to both sides of the equation to cancel out the 3h-3h on the right side.
6h+3h=4-6-h+3h=4

STEP 4

Simplify the left side of the equation by combining the h-h and 3h3h terms.
6+2h=4-6+2h=4

STEP 5

Next, we can isolate the variable hh on one side of the equation. To do this, we can add 66 to both sides of the equation to cancel out the 6-6 on the left side.
2h=4+62h=4+6

STEP 6

Simplify the right side of the equation by adding 44 and 66.
2h=102h=10

STEP 7

Finally, we can solve for hh by dividing both sides of the equation by 22.
h=10/2h=10/2

STEP 8

Calculate the value of hh.
h=5h=5
The equation has one solution, h=5h=5.

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