Solved on Nov 12, 2023

Find the most accurate statement about the given 6×66 \times 6 matrix AA, which could be the adjacency matrix of a graph or a digraph.

STEP 1

Assumptions1. The given matrix is a6x6 matrix. . The entries of the matrix are either0 or1.
3. The matrix represents an adjacency matrix of a graph or a digraph.
4. In an adjacency matrix for a graph, the matrix is symmetric because the edges have no direction. If there is an edge from vertex i to vertex j, there is also an edge from vertex j to vertex i.
5. In an adjacency matrix for a digraph, the matrix does not have to be symmetric because the edges have direction. If there is an edge from vertex i to vertex j, there is not necessarily an edge from vertex j to vertex i.

STEP 2

First, we need to check if the given matrix is symmetric. A matrix is symmetric if it is equal to its transpose.

STEP 3

The transpose of a matrix is obtained by interchanging its rows and columns. Let's find the transpose of the given matrix.

STEP 4

The transpose of the matrix A isA=(010111001011100111010000000000000110)A^=\left(\begin{array}{llllll} 0 &1 &0 &1 &1 &1 \\ 0 &0 &1 &0 &1 &1 \\ 1 &0 &0 &1 &1 &1 \\ 0 &1 &0 &0 &0 &0 \\ 0 &0 &0 &0 &0 &0 \\ 0 &0 &0 &1 &1 &0\end{array}\right)

STEP 5

Now, we compare the given matrix A with its transpose A^. If they are equal, then the matrix is symmetric and it represents a graph. If they are not equal, then it represents a digraph.

STEP 6

By comparing the matrix A and its transpose A^, we can see that they are not equal. Therefore, the matrix A is not symmetric.

STEP 7

Since the matrix A is not symmetric, it cannot represent a graph. Therefore, it must represent a digraph.
The statement "This must be the adjacency matrix for a digraph (it can't be a regular graph)" is most true.

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