Solved on Nov 02, 2023

Find missing y-values for $y = x^{2}$ when $x = 0, 1, 2$ in the given table: Input (x) | Output (y) -2 | 4, -1 | 1, 0 | ?, 1 | ?, 2 | ?

STEP 1

Assumptions1. The function is $y = x^{}$ . The values of $x$ we need to find $y$ for are $x =0$ , $x =1$ , and $x =$

STEP 2

The function $y = x^{2}$ means that for any given $x$ , $y$ is the square of $x$ . We can use this to find the missing $y$ -values in the table.

STEP 3

First, let's find the $y$ -value for $x =0$ . We can do this by substituting $x =0$ into the function.
$y = (0)^{2}$

STEP 4

Calculate the $y$ -value for $x =0$ .
$y = (0)^{2} =0$

STEP 5

Next, let's find the $y$ -value for $x =1$ . We can do this by substituting $x =1$ into the function.
$y = (1)^{2}$

STEP 6

Calculate the $y$ -value for $x =1$ .
$y = (1)^{2} =1$

STEP 7

Finally, let's find the $y$ -value for $x =2$ . We can do this by substituting $x =2$ into the function.
$y = (2)^{2}$

STEP 8

Calculate the $y$ -value for $x =2$ .
$y = (2)^{2} =4$

STEP 9

Now that we have found the missing $y$ -values, we can complete the table.
\begin{tabular}{|c|c|} \hline\text{Input} (x) & \text{Output} (y) \\ \hline-2 &4 \\ \hline- & \\ \hline & \\ \hline & \\ \hline2 &4 \\ \hline\end{tabular}
The missing $y$ -values in the table for $x =$ , $x =$ , and $x =2$ are,, and4 respectively.

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Find missing y-values for $y = x^{2}$ when $x = 0, 1, 2$ in the given table: Input (x) | Output (y) -2 | 4, -1 | 1, 0 | ?, 1 | ?, 2 | ?

STEP 1

Assumptions1. The function is $y = x^{}$ . The values of $x$ we need to find $y$ for are $x =0$ , $x =1$ , and $x =$

STEP 2

The function $y = x^{2}$ means that for any given $x$ , $y$ is the square of $x$ . We can use this to find the missing $y$ -values in the table.

STEP 3

First, let's find the $y$ -value for $x =0$ . We can do this by substituting $x =0$ into the function.
$y = (0)^{2}$

STEP 4

Calculate the $y$ -value for $x =0$ .
$y = (0)^{2} =0$

STEP 5

Next, let's find the $y$ -value for $x =1$ . We can do this by substituting $x =1$ into the function.
$y = (1)^{2}$

STEP 6

Calculate the $y$ -value for $x =1$ .
$y = (1)^{2} =1$

STEP 7

Finally, let's find the $y$ -value for $x =2$ . We can do this by substituting $x =2$ into the function.
$y = (2)^{2}$

STEP 8

Calculate the $y$ -value for $x =2$ .
$y = (2)^{2} =4$

STEP 9

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Find missing y-values for y=x2y = x^{2}y=x2 when x=0,1,2x = 0, 1, 2x=0,1,2 in the given table: Input (x) | Output (y) -2 | 4, -1 | 1, 0 | ?, 1 | ?, 2 | ?

STEP 1

Assumptions1. The function is y=xy = x^{}y=x . The values of xxx we need to find yyy for are x=0x =0x=0, x=1x =1x=1, and x=x =x=

STEP 2

The function y=x2y = x^{2}y=x2 means that for any given xxx, yyy is the square of xxx. We can use this to find the missing yyy-values in the table.

STEP 3

First, let's find the yyy-value for x=0x =0x=0. We can do this by substituting x=0x =0x=0 into the function.y=(0)2y = (0)^{2}y=(0)2

STEP 4

Calculate the yyy-value for x=0x =0x=0.y=(0)2=0y = (0)^{2} =0y=(0)2=0

STEP 5

Next, let's find the yyy-value for x=1x =1x=1. We can do this by substituting x=1x =1x=1 into the function.y=(1)2y = (1)^{2}y=(1)2

STEP 6

Calculate the yyy-value for x=1x =1x=1.y=(1)2=1y = (1)^{2} =1y=(1)2=1

STEP 7

Finally, let's find the yyy-value for x=2x =2x=2. We can do this by substituting x=2x =2x=2 into the function.y=(2)2y = (2)^{2}y=(2)2

STEP 8

Calculate the yyy-value for x=2x =2x=2.y=(2)2=4y = (2)^{2} =4y=(2)2=4

STEP 9

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Find missing y-values for $y = x^{2}$ when $x = 0, 1, 2$ in the given table: Input (x) | Output (y) -2 | 4, -1 | 1, 0 | ?, 1 | ?, 2 | ?

Assumptions1. The function is $y = x^{}$ . The values of $x$ we need to find $y$ for are $x =0$ , $x =1$ , and $x =$

The function $y = x^{2}$ means that for any given $x$ , $y$ is the square of $x$ . We can use this to find the missing $y$ -values in the table.

First, let's find the $y$ -value for $x =0$ . We can do this by substituting $x =0$ into the function.
$y = (0)^{2}$

Calculate the $y$ -value for $x =0$ .
$y = (0)^{2} =0$

Next, let's find the $y$ -value for $x =1$ . We can do this by substituting $x =1$ into the function.
$y = (1)^{2}$

Calculate the $y$ -value for $x =1$ .
$y = (1)^{2} =1$

Finally, let's find the $y$ -value for $x =2$ . We can do this by substituting $x =2$ into the function.
$y = (2)^{2}$

Calculate the $y$ -value for $x =2$ .
$y = (2)^{2} =4$