Solved on Dec 07, 2023

Find the percent decrease of water in a tank that contained $5 \mathrm{~cm}$ of water at noon and $3 \mathrm{~cm}$ after several hours.

STEP 1

Assumptions
1. Initial water level in the tank is $5 \mathrm{~cm}$ .
2. Final water level in the tank is $3 \mathrm{~cm}$ .
3. Percent decrease is calculated using the formula: $\text{Percent Decrease} = \frac{\text{Initial Value} - \text{Final Value}}{\text{Initial Value}} \times 100\%$

STEP 2

Calculate the decrease in water level by subtracting the final water level from the initial water level.
$\text{Decrease in water level} = \text{Initial water level} - \text{Final water level}$

STEP 3

Now, plug in the given values for the initial and final water levels to calculate the decrease in water level.
$\text{Decrease in water level} = 5 \mathrm{~cm} - 3 \mathrm{~cm}$

STEP 4

Calculate the decrease in water level.
$\text{Decrease in water level} = 2 \mathrm{~cm}$

STEP 5

Now we can calculate the percent decrease using the formula given in STEP_1.
$\text{Percent Decrease} = \frac{\text{Decrease in water level}}{\text{Initial water level}} \times 100\%$

STEP 6

Plug in the values for the decrease in water level and the initial water level to calculate the percent decrease.
$\text{Percent Decrease} = \frac{2 \mathrm{~cm}}{5 \mathrm{~cm}} \times 100\%$

STEP 7

Calculate the percent decrease.
$\text{Percent Decrease} = \frac{2}{5} \times 100\%$

STEP 8

Simplify the fraction and calculate the percent decrease.
$\text{Percent Decrease} = 0.4 \times 100\%$

STEP 9

Calculate the percent decrease.
$\text{Percent Decrease} = 40\%$
The percent decrease of water in the tank is $40\%$ .

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Find the percent decrease of water in a tank that contained $5 \mathrm{~cm}$ of water at noon and $3 \mathrm{~cm}$ after several hours.

STEP 1

Assumptions
1. Initial water level in the tank is $5 \mathrm{~cm}$ .
2. Final water level in the tank is $3 \mathrm{~cm}$ .
3. Percent decrease is calculated using the formula: $\text{Percent Decrease} = \frac{\text{Initial Value} - \text{Final Value}}{\text{Initial Value}} \times 100\%$

STEP 2

Calculate the decrease in water level by subtracting the final water level from the initial water level.
$\text{Decrease in water level} = \text{Initial water level} - \text{Final water level}$

STEP 3

Now, plug in the given values for the initial and final water levels to calculate the decrease in water level.
$\text{Decrease in water level} = 5 \mathrm{~cm} - 3 \mathrm{~cm}$

STEP 4

Calculate the decrease in water level.
$\text{Decrease in water level} = 2 \mathrm{~cm}$

STEP 5

Now we can calculate the percent decrease using the formula given in STEP_1.
$\text{Percent Decrease} = \frac{\text{Decrease in water level}}{\text{Initial water level}} \times 100\%$

STEP 6

Plug in the values for the decrease in water level and the initial water level to calculate the percent decrease.
$\text{Percent Decrease} = \frac{2 \mathrm{~cm}}{5 \mathrm{~cm}} \times 100\%$

STEP 7

Calculate the percent decrease.
$\text{Percent Decrease} = \frac{2}{5} \times 100\%$

STEP 8

Simplify the fraction and calculate the percent decrease.
$\text{Percent Decrease} = 0.4 \times 100\%$

STEP 9

Calculate the percent decrease.
$\text{Percent Decrease} = 40\%$
The percent decrease of water in the tank is $40\%$ .

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Find the percent decrease of water in a tank that contained 5 cm5 \mathrm{~cm}5 cm of water at noon and 3 cm3 \mathrm{~cm}3 cm after several hours.

STEP 1

STEP 2

STEP 3

Now, plug in the given values for the initial and final water levels to calculate the decrease in water level.Decrease in water level=5 cm−3 cm\text{Decrease in water level} = 5 \mathrm{~cm} - 3 \mathrm{~cm}Decrease in water level=5 cm−3 cm

STEP 4

Calculate the decrease in water level.Decrease in water level=2 cm\text{Decrease in water level} = 2 \mathrm{~cm}Decrease in water level=2 cm

STEP 5

STEP 6

Plug in the values for the decrease in water level and the initial water level to calculate the percent decrease.Percent Decrease=2 cm5 cm×100%\text{Percent Decrease} = \frac{2 \mathrm{~cm}}{5 \mathrm{~cm}} \times 100\%Percent Decrease=5 cm2 cm​×100%

STEP 7

Calculate the percent decrease.Percent Decrease=25×100%\text{Percent Decrease} = \frac{2}{5} \times 100\%Percent Decrease=52​×100%

STEP 8

Simplify the fraction and calculate the percent decrease.Percent Decrease=0.4×100%\text{Percent Decrease} = 0.4 \times 100\%Percent Decrease=0.4×100%

STEP 9

Calculate the percent decrease.Percent Decrease=40%\text{Percent Decrease} = 40\%Percent Decrease=40%The percent decrease of water in the tank is 40%40\%40%.

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Find the percent decrease of water in a tank that contained $5 \mathrm{~cm}$ of water at noon and $3 \mathrm{~cm}$ after several hours.

Now, plug in the given values for the initial and final water levels to calculate the decrease in water level.
$\text{Decrease in water level} = 5 \mathrm{~cm} - 3 \mathrm{~cm}$

Calculate the decrease in water level.
$\text{Decrease in water level} = 2 \mathrm{~cm}$

Plug in the values for the decrease in water level and the initial water level to calculate the percent decrease.
$\text{Percent Decrease} = \frac{2 \mathrm{~cm}}{5 \mathrm{~cm}} \times 100\%$

Calculate the percent decrease.
$\text{Percent Decrease} = \frac{2}{5} \times 100\%$

Simplify the fraction and calculate the percent decrease.
$\text{Percent Decrease} = 0.4 \times 100\%$

Calculate the percent decrease.
$\text{Percent Decrease} = 40\%$
The percent decrease of water in the tank is $40\%$ .