Solved on Feb 15, 2024

Solve the system of linear equations y=5y=5 and 3x+4y=8-3x+4y=8.

STEP 1

Assumptions
1. We have a system of linear equations: {y=53x+4y=8\left\{\begin{array}{r} y=5 \\ -3x+4y=8 \end{array}\right.
2. We need to find the values of xx and yy that satisfy both equations simultaneously.

STEP 2

Since the first equation directly gives us the value of yy, we can use it to find xx by substituting yy into the second equation.
y=5y=5

STEP 3

Substitute y=5y=5 into the second equation:
3x+4(5)=8-3x + 4(5) = 8

STEP 4

Simplify the equation by multiplying 4 by 5:
3x+20=8-3x + 20 = 8

STEP 5

Subtract 20 from both sides of the equation to isolate the term with xx:
3x=820-3x = 8 - 20

STEP 6

Calculate the right-hand side of the equation:
3x=12-3x = -12

STEP 7

Divide both sides of the equation by 3-3 to solve for xx:
x=123x = \frac{-12}{-3}

STEP 8

Calculate the value of xx:
x=4x = 4

STEP 9

Now that we have the value of xx, we can state the solution to the system of equations. We already know that y=5y=5 from the first equation.
The solution to the system of equations is x=4x=4 and y=5y=5.

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