Fractions and Decimals

Discrete Mathematics

Differential Equations

Solved on Jan 21, 2024

Stopping distance of car at $30$ mph is $y=2(30)+15$ , where $y$ is stopping distance in feet. What is the stopping distance?

STEP 1

Assumptions
1. The equation of the line of best fit for stopping distance versus speed is $y = 2x + 15$ .
2. The variable $y$ represents the stopping distance in feet.
3. The variable $x$ represents the speed of the car in mph (miles per hour).
4. We are asked to find the stopping distance for a car traveling at 30 mph.

STEP 2

To find the stopping distance for a car traveling at 30 mph, we need to substitute $x = 30$ into the equation of the line of best fit.
$y = 2x + 15$

STEP 3

Now, plug in $x = 30$ into the equation.
$y = 2(30) + 15$

STEP 4

Multiply $2$ by $30$ to find the first term.
$y = 60 + 15$

STEP 5

Add $60$ and $15$ to find the stopping distance $y$ .
$y = 60 + 15 = 75$
The stopping distance of a car traveling 30 mph is $75$ feet.

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