Solved on Nov 09, 2023

Find the number of adult tickets sold for a school play where 752 total tickets were sold, with 52 more student tickets than adult tickets.
Let $x$ be the number of adult tickets and $y$ be the number of student tickets. Then, $x + y = 752$ and $y = x + 52$ .

STEP 1

Assumptions1. The total number of tickets sold is752. . The tickets sold are either adult tickets or student tickets.
3. There were52 more student tickets sold than adult tickets.

STEP 2

Let's denote the number of adult tickets as $x$ and the number of student tickets as $y$ .

STEP 3

We know that the total number of tickets sold is the sum of the adult tickets and student tickets. Therefore, we can write the first equation as $x + y =752$

STEP 4

We also know that there were52 more student tickets sold than adult tickets. Therefore, we can write the second equation as $y = x +52$

STEP 5

Now we have a system of two equations. To solve it, we can substitute the second equation into the first one $x + (x +52) =752$

STEP 6

implify the equation $2x +52 =752$

STEP 7

Subtract52 from both sides of the equation $2x =752 -52$

STEP 8

Calculate the right side of the equation $2x =700$

STEP 9

Divide both sides of the equation by2 to solve for $x$ $x =700 /2$

STEP 10

Calculate the value of $x$ $x =350$ So,350 adult tickets were sold.

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Find the number of adult tickets sold for a school play where 752 total tickets were sold, with 52 more student tickets than adult tickets.
Let $x$ be the number of adult tickets and $y$ be the number of student tickets. Then, $x + y = 752$ and $y = x + 52$ .

STEP 1

Assumptions1. The total number of tickets sold is752. . The tickets sold are either adult tickets or student tickets.
3. There were52 more student tickets sold than adult tickets.

STEP 2

Let's denote the number of adult tickets as $x$ and the number of student tickets as $y$ .

STEP 3

We know that the total number of tickets sold is the sum of the adult tickets and student tickets. Therefore, we can write the first equation as $x + y =752$

STEP 4

We also know that there were52 more student tickets sold than adult tickets. Therefore, we can write the second equation as $y = x +52$

STEP 5

Now we have a system of two equations. To solve it, we can substitute the second equation into the first one $x + (x +52) =752$

STEP 6

implify the equation $2x +52 =752$

STEP 7

Subtract52 from both sides of the equation $2x =752 -52$

STEP 8

Calculate the right side of the equation $2x =700$

STEP 9

Divide both sides of the equation by2 to solve for $x$ $x =700 /2$

STEP 10

Calculate the value of $x$ $x =350$ So,350 adult tickets were sold.

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Find the number of adult tickets sold for a school play where 752 total tickets were sold, with 52 more student tickets than adult tickets.Let xxx be the number of adult tickets and yyy be the number of student tickets. Then, x+y=752x + y = 752x+y=752 and y=x+52y = x + 52y=x+52.

STEP 1

Assumptions1. The total number of tickets sold is752. . The tickets sold are either adult tickets or student tickets.3. There were52 more student tickets sold than adult tickets.

STEP 2

Let's denote the number of adult tickets as xxx and the number of student tickets as yyy.

STEP 3

We know that the total number of tickets sold is the sum of the adult tickets and student tickets. Therefore, we can write the first equation asx+y=752x + y =752x+y=752

STEP 4

We also know that there were52 more student tickets sold than adult tickets. Therefore, we can write the second equation asy=x+52y = x +52y=x+52

STEP 5

Now we have a system of two equations. To solve it, we can substitute the second equation into the first onex+(x+52)=752x + (x +52) =752x+(x+52)=752

STEP 6

implify the equation2x+52=7522x +52 =7522x+52=752

STEP 7

Subtract52 from both sides of the equation2x=752−522x =752 -522x=752−52

STEP 8

Calculate the right side of the equation2x=7002x =7002x=700

STEP 9

Divide both sides of the equation by2 to solve for xxxx=700/2x =700 /2x=700/2

STEP 10

Calculate the value of xxxx=350x =350x=350So,350 adult tickets were sold.

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Find the number of adult tickets sold for a school play where 752 total tickets were sold, with 52 more student tickets than adult tickets.
Let $x$ be the number of adult tickets and $y$ be the number of student tickets. Then, $x + y = 752$ and $y = x + 52$ .

Assumptions1. The total number of tickets sold is752. . The tickets sold are either adult tickets or student tickets.
3. There were52 more student tickets sold than adult tickets.

Let's denote the number of adult tickets as $x$ and the number of student tickets as $y$ .

We know that the total number of tickets sold is the sum of the adult tickets and student tickets. Therefore, we can write the first equation as $x + y =752$

We also know that there were52 more student tickets sold than adult tickets. Therefore, we can write the second equation as $y = x +52$

Now we have a system of two equations. To solve it, we can substitute the second equation into the first one $x + (x +52) =752$

implify the equation $2x +52 =752$

Subtract52 from both sides of the equation $2x =752 -52$

Calculate the right side of the equation $2x =700$

Divide both sides of the equation by2 to solve for $x$ $x =700 /2$

Calculate the value of $x$ $x =350$ So,350 adult tickets were sold.