Solved on Dec 07, 2023

Solve 3(2g+2.5)=15.93(2 g+2.5)=15.9 for gg. Determine if the given solution is correct and find the correct value of gg.

STEP 1

Assumptions
1. The original equation is 3(2g+2.5)=15.93(2g + 2.5) = 15.9.
2. The goal is to solve for the variable gg.
3. The steps provided in the problem statement are to be verified for correctness.

STEP 2

Let's first verify the steps provided in the problem statement.
The first step is to distribute the 3 across the terms inside the parentheses:
3(2g+2.5)=15.93(2g + 2.5) = 15.9

STEP 3

Distribute the 3 to both terms inside the parentheses:
32g+32.5=15.93 \cdot 2g + 3 \cdot 2.5 = 15.9

STEP 4

Perform the multiplication:
6g+7.5=15.96g + 7.5 = 15.9

STEP 5

Now, let's identify the error in the provided steps. The next step in the problem statement incorrectly states:
6g=23.46g = 23.4
This is incorrect because the correct step should involve subtracting 7.5 from both sides of the equation to isolate the term with gg.

STEP 6

Subtract 7.5 from both sides of the equation to isolate the 6g6g term:
6g+7.57.5=15.97.56g + 7.5 - 7.5 = 15.9 - 7.5

STEP 7

Perform the subtraction:
6g=15.97.56g = 15.9 - 7.5

STEP 8

Calculate the right side of the equation:
6g=8.46g = 8.4

STEP 9

Now, to solve for gg, divide both sides of the equation by 6:
6g6=8.46\frac{6g}{6} = \frac{8.4}{6}

STEP 10

Perform the division:
g=1.4g = 1.4

STEP 11

To verify the solution, plug g=1.4g = 1.4 back into the original equation:
3(2(1.4)+2.5)=15.93(2(1.4) + 2.5) = 15.9

STEP 12

First, calculate the value inside the parentheses:
2(1.4)+2.5=2.8+2.52(1.4) + 2.5 = 2.8 + 2.5

STEP 13

Add the values:
2.8+2.5=5.32.8 + 2.5 = 5.3

STEP 14

Now, multiply this result by 3:
35.3=15.93 \cdot 5.3 = 15.9

STEP 15

Perform the multiplication:
15.9=15.915.9 = 15.9

STEP 16

Since the left side of the equation equals the right side, our solution for gg is verified.
a) The provided steps are incorrect because the subtraction step was not performed correctly.
b) The correct value of gg is 1.41.4, and the verification shows that this solution satisfies the original equation.

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