Solved on Nov 16, 2023

A patient takes $7$daystorecoverfromasurgicalprocedurewithameanrecoverytimeof\$7\$ days to recover from a surgical procedure with a mean recovery time of \4.9$daysandastandarddeviationof4.9\$ days and a standard deviation of \2.1$days.Findthepatients2.1\$ days. Find the patient's z$-score. (Round to two decimal places.)

STEP 1

Assumptions1. The recovery time from the surgical procedure is normally distributed. . The mean recovery time is4.9 days.
3. The standard deviation of the recovery time is.1 days.
4. We are asked to find the zz-score for a patient who takes7 days to recover.

STEP 2

The formula for calculating a zz-score isz=Xμσz = \frac{X - \mu}{\sigma}where XX is the value from the dataset (in this case, the recovery time of the patient), μ\mu is the mean of the dataset, and σ\sigma is the standard deviation of the dataset.

STEP 3

Now, plug in the given values for XX, μ\mu, and σ\sigma to calculate the zz-score.
z=7.92.1z = \frac{7 -.9}{2.1}

STEP 4

First, calculate the difference between XX and μ\mu.
74.9=2.17 -4.9 =2.1So, the zz-score becomesz=2.12.1z = \frac{2.1}{2.1}

STEP 5

Finally, calculate the zz-score.
z=2.12.1=1z = \frac{2.1}{2.1} =1So, the zz-score for a patient who takes7 days to recover is1.00 (rounded to two decimal places).

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