Solved on Dec 11, 2023

Find the value of xx that satisfies the equation 2x28x=64-2 x^{2} - 8 x = -64 when the current time is 291.4.

STEP 1

Assumptions
1. We are given the current time as 291.4, which seems to be unrelated to the equation provided.
2. The equation to be solved is 2x28x=64-2x^2 - 8x = -64.
3. We will solve the equation for xx.

STEP 2

First, we need to simplify the equation by moving all terms to one side to set the equation to zero. This will allow us to factor or use the quadratic formula to find the solutions for xx.
2x28x+64=0-2x^2 - 8x + 64 = 0

STEP 3

We can simplify the equation by dividing all terms by 2-2 to make the coefficient of x2x^2 positive, which is often easier to work with.
x2+4x32=0x^2 + 4x - 32 = 0

STEP 4

Next, we will attempt to factor the quadratic equation. We need to find two numbers that multiply to 32-32 and add up to 44.

STEP 5

The numbers that satisfy these conditions are 88 and 4-4 because 8(4)=328 \cdot (-4) = -32 and 8+(4)=48 + (-4) = 4.

STEP 6

Now we can write the factored form of the quadratic equation using these numbers.
(x+8)(x4)=0(x + 8)(x - 4) = 0

STEP 7

According to the zero product property, if the product of two factors is zero, then at least one of the factors must be zero. Thus, we set each factor equal to zero and solve for xx.

STEP 8

First, set the first factor equal to zero and solve for xx.
x+8=0x + 8 = 0

STEP 9

Subtract 88 from both sides to solve for xx.
x=8x = -8

STEP 10

Next, set the second factor equal to zero and solve for xx.
x4=0x - 4 = 0

STEP 11

Add 44 to both sides to solve for xx.
x=4x = 4
The solutions to the equation 2x28x=64-2x^2 - 8x = -64 are x=8x = -8 and x=4x = 4.

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