Solved on Nov 26, 2023

Find the initial number of people ill with the flu, given the function N(t)=50001+999etN(t)=\frac{5000}{1+999 e^{-t}} models the number of people ill tt weeks after the outbreak. Round the result to the nearest person.

STEP 1

Assumptions1. The function (t)=50001+999et(t)=\frac{5000}{1+999 e^{-t}} models the number of people who have caught the flu tt weeks after the initial outbreak. . The number of people ill initially is represented by (0)(0).

STEP 2

To find the number of people who were ill initially, we need to evaluate the function at t=0t=0.(0)=50001+999e0(0)=\frac{5000}{1+999 e^{-0}}

STEP 3

implify the expression inside the exponential function. Since any number raised to the power of0 is1, we havee0=e0=1e^{-0} = e^{0} =1So, the function becomes(0)=50001+999×1(0)=\frac{5000}{1+999 \times1}

STEP 4

implify the denominator.
(0)=50001+999=50001000(0)=\frac{5000}{1+999} = \frac{5000}{1000}

STEP 5

Calculate the value of (0)(0).
(0)=50001000=5(0) = \frac{5000}{1000} =5So, initially, there were5 people ill. Since we cannot have a fraction of a person, we round to the nearest whole number. Therefore, the answer is5 people.

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