Fractions and Decimals

Discrete Mathematics

Differential Equations

Solved on Nov 21, 2023

Find the range of the cost function $C = 98 + 0.12n$ for newspaper printing. Express the range as $C \geq y$ and the domain as $n \geq x$ .

STEP 1

Assumptions1. The equation $C =98 +0.12n$ represents the total cost ( $C$ ) of printing newspapers, where $n$ is the number of newspapers printed. . The domain of the relation is all possible values of $n$ and can be expressed in the form $n \geq x$ .
3. The range of the relation is all possible values of $C$ and can be expressed in the form $C \geq y$ .

STEP 2

The domain of the relation is all possible values of $n$ . Since $n$ represents the number of newspapers printed, it cannot be negative. Therefore, the smallest possible value for $n$ is0. So, $x =0$ .
$n \geq0$

STEP 3

The range of the relation is all possible values of $C$ . To find the smallest possible value for $C$ , we substitute the smallest possible value for $n$ (which is0) into the equation.
$C =98 +0.12n$

STEP 4

Substitute $n =0$ into the equation.
$C =98 +0.12 \times0$

STEP 5

Calculate the value of $C$ .
$C =98 +0 =98$ Therefore, the smallest possible value for $C$ is98. So, $y =98$ .
$C \geq98$ So, the value of $y$ is98 and the value of $x$ is0.

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