Solved on Oct 27, 2023

Find the possible number of hours the chemistry club can rent a meeting room with a $15 reservation fee and$ 6 per hour fee, given a maximum budget of $63.
Let $t$ be the number of hours. The inequality is: $15 + 6t \leq 63$ .

STEP 1

Assumptions1. The reservation fee is $15. The additional fee per hour is$ 63. The chemistry club wants to spend at most $634. The total cost is the sum of the reservation fee and the product of the additional fee per hour and the number of hours

STEP 2

First, we need to set up an inequality that represents the total cost of renting the room. The total cost is the sum of the reservation fee and the product of the additional fee per hour and the number of hours.
$Total\, cost = Reservation\, fee + (Additional\, fee\, per\, hour \\times Number\, of\, hours)$

STEP 3

Now, plug in the given values for the reservation fee and the additional fee per hour.
$Total\, cost = \$15 + (\$6 \\times t)$

STEP 4

The chemistry club wants to spend at most $63, so we set up the inequality as follows$ $\$15 + \$6t \leq \$63$ $

STEP 5

We want to solve for $t$ , so we need to isolate $t$ on one side of the inequality. We can do this by subtracting $15 from both sides of the inequality.
$\$t \leq \$63 - \$15$

STEP 6

Calculate the right side of the inequality.
$\$6t \leq \$48$

STEP 7

Finally, to solve for $t$ , we divide both sides of the inequality by $6$ .
$t \leq \$48 / \$6$

STEP 8

Calculate the right side of the inequality.
$t \leq8$ The chemistry club can rent the meeting room for at most8 hours.

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Find the possible number of hours the chemistry club can rent a meeting room with a $15 reservation fee and$ 6 per hour fee, given a maximum budget of $63.
Let $t$ be the number of hours. The inequality is: $15 + 6t \leq 63$ .

STEP 1

Assumptions1. The reservation fee is $15. The additional fee per hour is$ 63. The chemistry club wants to spend at most $634. The total cost is the sum of the reservation fee and the product of the additional fee per hour and the number of hours

STEP 2

STEP 3

Now, plug in the given values for the reservation fee and the additional fee per hour.
$Total\, cost = \$15 + (\$6 \\times t)$

STEP 4

The chemistry club wants to spend at most $63, so we set up the inequality as follows$ $\$15 + \$6t \leq \$63$ $

STEP 5

We want to solve for $t$ , so we need to isolate $t$ on one side of the inequality. We can do this by subtracting $15 from both sides of the inequality.
$\$t \leq \$63 - \$15$

STEP 6

Calculate the right side of the inequality.
$\$6t \leq \$48$

STEP 7

Finally, to solve for $t$ , we divide both sides of the inequality by $6$ .
$t \leq \$48 / \$6$

STEP 8

Calculate the right side of the inequality.
$t \leq8$ The chemistry club can rent the meeting room for at most8 hours.

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Find the possible number of hours the chemistry club can rent a meeting room with a 15reservationfeeand15 reservation fee and 15reservationfeeand6 per hour fee, given a maximum budget of $63.Let ttt be the number of hours. The inequality is: 15+6t≤6315 + 6t \leq 6315+6t≤63.

STEP 1

Assumptions1. The reservation fee is 15.Theadditionalfeeperhouris15. The additional fee per hour is 15.Theadditionalfeeperhouris63. The chemistry club wants to spend at most $634. The total cost is the sum of the reservation fee and the product of the additional fee per hour and the number of hours

STEP 2

STEP 3

Now, plug in the given values for the reservation fee and the additional fee per hour.Total cost=$15+($6timest)Total\, cost = \$15 + (\$6 \\times t)Totalcost=$15+($6timest)

STEP 4

The chemistry club wants to spend at most 63,sowesetuptheinequalityasfollows63, so we set up the inequality as follows63,sowesetuptheinequalityasfollows$15+$6t≤$63\$15 + \$6t \leq \$63$15+$6t≤$63$

STEP 5

We want to solve for ttt, so we need to isolate ttt on one side of the inequality. We can do this by subtracting $15 from both sides of the inequality.$t≤$63−$15\$t \leq \$63 - \$15$t≤$63−$15

STEP 6

Calculate the right side of the inequality.$6t≤$48\$6t \leq \$48$6t≤$48

STEP 7

Finally, to solve for ttt, we divide both sides of the inequality by 666.t≤$48/$6t \leq \$48 / \$6t≤$48/$6

STEP 8

Calculate the right side of the inequality.t≤8t \leq8t≤8The chemistry club can rent the meeting room for at most8 hours.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Find the possible number of hours the chemistry club can rent a meeting room with a $15 reservation fee and$ 6 per hour fee, given a maximum budget of $63.
Let $t$ be the number of hours. The inequality is: $15 + 6t \leq 63$ .

Assumptions1. The reservation fee is $15. The additional fee per hour is$ 63. The chemistry club wants to spend at most $634. The total cost is the sum of the reservation fee and the product of the additional fee per hour and the number of hours

Now, plug in the given values for the reservation fee and the additional fee per hour.
$Total\, cost = \$15 + (\$6 \\times t)$

The chemistry club wants to spend at most $63, so we set up the inequality as follows$ $\$15 + \$6t \leq \$63$ $

We want to solve for $t$ , so we need to isolate $t$ on one side of the inequality. We can do this by subtracting $15 from both sides of the inequality.
$\$t \leq \$63 - \$15$

Calculate the right side of the inequality.
$\$6t \leq \$48$

Finally, to solve for $t$ , we divide both sides of the inequality by $6$ .
$t \leq \$48 / \$6$

Calculate the right side of the inequality.
$t \leq8$ The chemistry club can rent the meeting room for at most8 hours.