Solved on Feb 25, 2024

Solve the system of linear equations 5x+8y=0-5x + 8y = 0 and 7x8y=96-7x - 8y = -96.

STEP 1

Assumptions
1. We have a system of two linear equations: \begin{align*} -5x + 8y &= 0 \\ -7x - 8y &= -96 \end{align*}
2. We need to find the values of xx and yy that satisfy both equations.

STEP 2

We can use the method of elimination to solve this system of equations. First, we will add the two equations together to eliminate yy.

STEP 3

Add the two equations: \begin{align*} (-5x + 8y) + (-7x - 8y) &= 0 + (-96) \end{align*}

STEP 4

Combine like terms: \begin{align*} -5x - 7x + 8y - 8y &= -96 \end{align*}

STEP 5

Simplify the equation: \begin{align*} -12x &= -96 \end{align*}

STEP 6

Divide both sides of the equation by 12-12 to solve for xx: \begin{align*} x &= \frac{-96}{-12} \end{align*}

STEP 7

Calculate the value of xx: \begin{align*} x &= 8 \end{align*}

STEP 8

Now that we have the value of xx, we can substitute it back into one of the original equations to solve for yy. We will use the first equation: \begin{align*} -5x + 8y &= 0 \end{align*}

STEP 9

Substitute x=8x = 8 into the equation: \begin{align*} -5(8) + 8y &= 0 \end{align*}

STEP 10

Simplify the equation: \begin{align*} -40 + 8y &= 0 \end{align*}

STEP 11

Add 4040 to both sides of the equation to solve for yy: \begin{align*} 8y &= 40 \end{align*}

STEP 12

Divide both sides of the equation by 88: \begin{align*} y &= \frac{40}{8} \end{align*}

STEP 13

Calculate the value of yy: \begin{align*} y &= 5 \end{align*}
The solution to the system of equations is x=8x = 8 and y=5y = 5.

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