Solved on Oct 30, 2023

Solve the inequality 82+b>2316\frac{8}{2} + b > \frac{23}{16}. Enter the solution as an interval, using "oo" for \infty, and fractions in reduced form.

STEP 1

Assumptions1. The inequality to solve is 8+b>2316\frac{8}{}+b>\frac{23}{16}

STEP 2

First, simplify the left side of the inequality. The fraction 82\frac{8}{2} simplifies to4.
4+b>23164+b>\frac{23}{16}

STEP 3

To isolate bb, subtract from both sides of the inequality.
b>2316b>\frac{23}{16}-

STEP 4

To subtract4 from 2316\frac{23}{16}, we need to express4 as a fraction with16 as the denominator.4 is equivalent to 6416\frac{64}{16}.
b>23166416b>\frac{23}{16}-\frac{64}{16}

STEP 5

Subtract the fractions on the right side of the inequality.
b>236416b>\frac{23-64}{16}

STEP 6

Calculate the numerator of the fraction on the right side of the inequality.
b>4116b>\frac{-41}{16}The solution to the inequality is b>4116b>\frac{-41}{16}, or in interval notation, b(4116,oo)b\in (\frac{-41}{16}, oo).

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