Solved on Dec 05, 2023

Solve 5 place-value subtraction problems using blocks if needed. $45-0=?$ , $68-49=?$ , $84-37=?$ , $99-33=?$ , $78-18=?$

STEP 1

Assumptions
1. We are performing subtraction using place-value blocks or conceptually understanding place-value.
2. We need to find the difference for each pair of numbers given.
3. We will use regrouping (borrowing) where necessary.

STEP 2

Let's solve the first subtraction problem.
$45 - 0 = ?$
Since we are subtracting zero, the value will not change.

STEP 3

Calculate the first subtraction.
$45 - 0 = 45$

STEP 4

Now, let's solve the second subtraction problem.
$68 - 49 = ?$
We need to regroup because we cannot subtract 9 from 8 in the ones place.

STEP 5

Regroup by borrowing 1 ten (which is equal to 10 ones) from the tens place.
$68 - 49 = (60 + 8) - (40 + 9)$
$= (50 + 18) - (40 + 9)$

STEP 6

Subtract the ones place.
$18 - 9 = 9$

STEP 7

Subtract the tens place.
$50 - 40 = 10$

STEP 8

Combine the tens and ones place to get the final answer for the second problem.
$10 + 9 = 19$

STEP 9

Now, let's solve the third subtraction problem.
$84 - 37 = ?$
We need to regroup because we cannot subtract 7 from 4 in the ones place.

STEP 10

Regroup by borrowing 1 ten (which is equal to 10 ones) from the tens place.
$84 - 37 = (80 + 4) - (30 + 7)$
$= (70 + 14) - (30 + 7)$

STEP 11

Subtract the ones place.
$14 - 7 = 7$

STEP 12

Subtract the tens place.
$70 - 30 = 40$

STEP 13

Combine the tens and ones place to get the final answer for the third problem.
$40 + 7 = 47$

STEP 14

Now, let's solve the fourth subtraction problem.
$99 - 33 = ?$
We do not need to regroup because we can subtract 3 from 9 in both the tens and ones places.

STEP 15

Subtract the ones place.
$9 - 3 = 6$

STEP 16

Subtract the tens place.
$90 - 30 = 60$

STEP 17

Combine the tens and ones place to get the final answer for the fourth problem.
$60 + 6 = 66$

STEP 18

Finally, let's solve the fifth subtraction problem.
$78 - 18 = ?$
We do not need to regroup because we can subtract 8 from 8 in the ones place and 1 from 7 in the tens place.

STEP 19

Subtract the ones place.
$8 - 8 = 0$

STEP 20

Subtract the tens place.
$70 - 10 = 60$

STEP 21

Combine the tens and ones place to get the final answer for the fifth problem.
$60 + 0 = 60$
The solutions to the subtraction problems are as follows:
1. $45 - 0 = 45$
2. $68 - 49 = 19$
3. $84 - 37 = 47$
4. $99 - 33 = 66$
5. $78 - 18 = 60$

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Solve 5 place-value subtraction problems using blocks if needed. 45−0=?45-0=?45−0=?, 68−49=?68-49=?68−49=?, 84−37=?84-37=?84−37=?, 99−33=?99-33=?99−33=?, 78−18=?78-18=?78−18=?

STEP 1

Assumptions1. We are performing subtraction using place-value blocks or conceptually understanding place-value.2. We need to find the difference for each pair of numbers given.3. We will use regrouping (borrowing) where necessary.

STEP 2

Let's solve the first subtraction problem.45−0=?45 - 0 = ?45−0=?Since we are subtracting zero, the value will not change.

STEP 3

Calculate the first subtraction.45−0=4545 - 0 = 4545−0=45

STEP 4

Now, let's solve the second subtraction problem.68−49=?68 - 49 = ?68−49=?We need to regroup because we cannot subtract 9 from 8 in the ones place.

STEP 5

Regroup by borrowing 1 ten (which is equal to 10 ones) from the tens place.68−49=(60+8)−(40+9)68 - 49 = (60 + 8) - (40 + 9)68−49=(60+8)−(40+9)=(50+18)−(40+9)= (50 + 18) - (40 + 9)=(50+18)−(40+9)

STEP 6

Subtract the ones place.18−9=918 - 9 = 918−9=9

STEP 7

Subtract the tens place.50−40=1050 - 40 = 1050−40=10

STEP 8

Combine the tens and ones place to get the final answer for the second problem.10+9=1910 + 9 = 1910+9=19

STEP 9

Now, let's solve the third subtraction problem.84−37=?84 - 37 = ?84−37=?We need to regroup because we cannot subtract 7 from 4 in the ones place.

STEP 10

Regroup by borrowing 1 ten (which is equal to 10 ones) from the tens place.84−37=(80+4)−(30+7)84 - 37 = (80 + 4) - (30 + 7)84−37=(80+4)−(30+7)=(70+14)−(30+7)= (70 + 14) - (30 + 7)=(70+14)−(30+7)

STEP 11

Subtract the ones place.14−7=714 - 7 = 714−7=7

STEP 12

Subtract the tens place.70−30=4070 - 30 = 4070−30=40

STEP 13

Combine the tens and ones place to get the final answer for the third problem.40+7=4740 + 7 = 4740+7=47

STEP 14

Now, let's solve the fourth subtraction problem.99−33=?99 - 33 = ?99−33=?We do not need to regroup because we can subtract 3 from 9 in both the tens and ones places.

STEP 15

Subtract the ones place.9−3=69 - 3 = 69−3=6

STEP 16

Subtract the tens place.90−30=6090 - 30 = 6090−30=60

STEP 17

Combine the tens and ones place to get the final answer for the fourth problem.60+6=6660 + 6 = 6660+6=66

STEP 18

Finally, let's solve the fifth subtraction problem.78−18=?78 - 18 = ?78−18=?We do not need to regroup because we can subtract 8 from 8 in the ones place and 1 from 7 in the tens place.

STEP 19

Subtract the ones place.8−8=08 - 8 = 08−8=0

STEP 20

Subtract the tens place.70−10=6070 - 10 = 6070−10=60

STEP 21

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Solve 5 place-value subtraction problems using blocks if needed. $45-0=?$ , $68-49=?$ , $84-37=?$ , $99-33=?$ , $78-18=?$

Assumptions
1. We are performing subtraction using place-value blocks or conceptually understanding place-value.
2. We need to find the difference for each pair of numbers given.
3. We will use regrouping (borrowing) where necessary.

Let's solve the first subtraction problem.
$45 - 0 = ?$
Since we are subtracting zero, the value will not change.

Calculate the first subtraction.
$45 - 0 = 45$

Now, let's solve the second subtraction problem.
$68 - 49 = ?$
We need to regroup because we cannot subtract 9 from 8 in the ones place.

Regroup by borrowing 1 ten (which is equal to 10 ones) from the tens place.
$68 - 49 = (60 + 8) - (40 + 9)$
$= (50 + 18) - (40 + 9)$

Subtract the ones place.
$18 - 9 = 9$

Subtract the tens place.
$50 - 40 = 10$

Combine the tens and ones place to get the final answer for the second problem.
$10 + 9 = 19$

Now, let's solve the third subtraction problem.
$84 - 37 = ?$
We need to regroup because we cannot subtract 7 from 4 in the ones place.

Regroup by borrowing 1 ten (which is equal to 10 ones) from the tens place.
$84 - 37 = (80 + 4) - (30 + 7)$
$= (70 + 14) - (30 + 7)$

Subtract the ones place.
$14 - 7 = 7$

Subtract the tens place.
$70 - 30 = 40$

Combine the tens and ones place to get the final answer for the third problem.
$40 + 7 = 47$

Now, let's solve the fourth subtraction problem.
$99 - 33 = ?$
We do not need to regroup because we can subtract 3 from 9 in both the tens and ones places.

Subtract the ones place.
$9 - 3 = 6$

Subtract the tens place.
$90 - 30 = 60$

Combine the tens and ones place to get the final answer for the fourth problem.
$60 + 6 = 66$

Finally, let's solve the fifth subtraction problem.
$78 - 18 = ?$
We do not need to regroup because we can subtract 8 from 8 in the ones place and 1 from 7 in the tens place.

Subtract the ones place.
$8 - 8 = 0$

Subtract the tens place.
$70 - 10 = 60$