Solved on Sep 18, 2023

Solve for xx in the linear equation kx+2=3bk x + 2 = 3 b.

STEP 1

Assumptions1. The equation is kx+=3bkx + =3b . We are solving for 'x'

STEP 2

First, we need to isolate 'x' on one side of the equation. We can do this by subtracting '2' from both sides of the equation.
kx+22=b2kx +2 -2 =b -2

STEP 3

implify the equation.
kx=3b2kx =3b -2

STEP 4

Now, to solve for 'x', we need to divide both sides of the equation by 'k'.
kxk=3b2k\frac{kx}{k} = \frac{3b -2}{k}

STEP 5

implify the equation to find the value of 'x'.
x=3b2kx = \frac{3b -2}{k}So, the solution to the equation is x=3b2kx = \frac{3b -2}{k}.

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