Solved on Feb 20, 2024

Solve 2(gh)=b+42(g-h)=b+4 for gg. Options: (A) g=b+h+4g=b+h+4 (B) g=b+2h+4g=b+2h+4 (C) g=b+h+2g=b+h+2 g=b2+h+2g=\frac{b}{2}+h+2

STEP 1

Assumptions
1. The equation to solve is 2(gh)=b+42(g-h)=b+4.
2. We need to solve for gg.

STEP 2

First, we will distribute the 2 on the left side of the equation to both gg and h-h.
2(gh)=2g2h2(g-h) = 2g - 2h

STEP 3

Now, rewrite the equation with the distributed terms.
2g2h=b+42g - 2h = b + 4

STEP 4

Next, we want to isolate gg on one side of the equation. To do this, we will add 2h2h to both sides of the equation to move the term involving hh to the right side.
2g2h+2h=b+4+2h2g - 2h + 2h = b + 4 + 2h

STEP 5

Simplify both sides of the equation by combining like terms.
2g=b+4+2h2g = b + 4 + 2h

STEP 6

To solve for gg, we need to divide both sides of the equation by 2.
2g2=b+4+2h2\frac{2g}{2} = \frac{b + 4 + 2h}{2}

STEP 7

Simplify the equation by performing the division.
g=b2+2+hg = \frac{b}{2} + 2 + h

STEP 8

Rearrange the terms to match the format of the answer choices.
g=b2+h+2g = \frac{b}{2} + h + 2
The solution to the equation 2(gh)=b+42(g-h)=b+4 for gg is g=b2+h+2g = \frac{b}{2} + h + 2.

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