Solved on Jan 16, 2024

Solve the linear equation: 86=8y+2-86 = -8y + 2

STEP 1

Assumptions
1. We have the equation 86=8y+2-86 = -8y + 2.
2. We need to solve for the variable yy.

STEP 2

First, we need to isolate the term containing yy on one side of the equation. We can do this by moving the constant term on the right side of the equation to the left side.
862=8y+22-86 - 2 = -8y + 2 - 2

STEP 3

Perform the subtraction on the left side of the equation.
862=8y-86 - 2 = -8y

STEP 4

Combine the constants on the left side.
88=8y-88 = -8y

STEP 5

Now, we need to solve for yy by isolating it. We can do this by dividing both sides of the equation by the coefficient of yy, which is 8-8.
888=8y8\frac{-88}{-8} = \frac{-8y}{-8}

STEP 6

Perform the division on both sides.
y=888y = \frac{-88}{-8}

STEP 7

Simplify the fraction to find the value of yy.
y=11y = 11
The solution to the equation 86=8y+2-86 = -8y + 2 is y=11y = 11.

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