Solved on Nov 07, 2023

Solve the linear equation $10x + 8(10x - 6) = 0$ for $x$ .

STEP 1

Assumptions1. The equation to solve is $10x +8(10x -6)$ . We are solving for the variable $x$

STEP 2

First, we need to distribute the $8$ to both terms inside the parentheses.
$10x +8(10x -6) =10x +80x -48$

STEP 3

Now, we simplify the equation by combining like terms.
$10x +80x -48 =90x -48$

STEP 4

The equation is now in the form $ax = b$ , where $a$ is the coefficient of $x$ and $b$ is a constant. To solve for $x$ , we need to isolate $x$ by dividing both sides of the equation by $a$ .
$x = \frac{b}{a}$

STEP 5

Plug in the values for $a$ and $b$ from our equation $90x -48$ to solve for $x$ .
$x = \frac{48}{90}$

STEP 6

implify the fraction to get the value of $x$ .
$x = \frac{48}{90} = \frac{8}{15}$ The solution to the equation $10x +8(10x -6)$ is $x = \frac{8}{15}$ .

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Solve the linear equation $10x + 8(10x - 6) = 0$ for $x$ .

STEP 1

Assumptions1. The equation to solve is $10x +8(10x -6)$ . We are solving for the variable $x$

STEP 2

First, we need to distribute the $8$ to both terms inside the parentheses.
$10x +8(10x -6) =10x +80x -48$

STEP 3

Now, we simplify the equation by combining like terms.
$10x +80x -48 =90x -48$

STEP 4

The equation is now in the form $ax = b$ , where $a$ is the coefficient of $x$ and $b$ is a constant. To solve for $x$ , we need to isolate $x$ by dividing both sides of the equation by $a$ .
$x = \frac{b}{a}$

STEP 5

Plug in the values for $a$ and $b$ from our equation $90x -48$ to solve for $x$ .
$x = \frac{48}{90}$

STEP 6

implify the fraction to get the value of $x$ .
$x = \frac{48}{90} = \frac{8}{15}$ The solution to the equation $10x +8(10x -6)$ is $x = \frac{8}{15}$ .

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Solve the linear equation 10x+8(10x−6)=010x + 8(10x - 6) = 010x+8(10x−6)=0 for xxx.

STEP 1

Assumptions1. The equation to solve is 10x+8(10x−6)10x +8(10x -6)10x+8(10x−6). We are solving for the variable xxx

STEP 2

First, we need to distribute the 888 to both terms inside the parentheses.10x+8(10x−6)=10x+80x−4810x +8(10x -6) =10x +80x -4810x+8(10x−6)=10x+80x−48

STEP 3

Now, we simplify the equation by combining like terms.10x+80x−48=90x−4810x +80x -48 =90x -4810x+80x−48=90x−48

STEP 4

The equation is now in the form ax=bax = bax=b, where aaa is the coefficient of xxx and bbb is a constant. To solve for xxx, we need to isolate xxx by dividing both sides of the equation by aaa.x=bax = \frac{b}{a}x=ab​

STEP 5

Plug in the values for aaa and bbb from our equation 90x−4890x -4890x−48 to solve for xxx.x=4890x = \frac{48}{90}x=9048​

STEP 6

implify the fraction to get the value of xxx.x=4890=815x = \frac{48}{90} = \frac{8}{15}x=9048​=158​The solution to the equation 10x+8(10x−6)10x +8(10x -6)10x+8(10x−6) is x=815x = \frac{8}{15}x=158​.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Solve the linear equation $10x + 8(10x - 6) = 0$ for $x$ .

Assumptions1. The equation to solve is $10x +8(10x -6)$ . We are solving for the variable $x$

First, we need to distribute the $8$ to both terms inside the parentheses.
$10x +8(10x -6) =10x +80x -48$

Now, we simplify the equation by combining like terms.
$10x +80x -48 =90x -48$

The equation is now in the form $ax = b$ , where $a$ is the coefficient of $x$ and $b$ is a constant. To solve for $x$ , we need to isolate $x$ by dividing both sides of the equation by $a$ .
$x = \frac{b}{a}$

Plug in the values for $a$ and $b$ from our equation $90x -48$ to solve for $x$ .
$x = \frac{48}{90}$

implify the fraction to get the value of $x$ .
$x = \frac{48}{90} = \frac{8}{15}$ The solution to the equation $10x +8(10x -6)$ is $x = \frac{8}{15}$ .