Solved on Feb 04, 2024

Solve for $x$ : $x+8=60$ , $\frac{x}{4}=50$ , $x^{2}=400$ , $54=9 x$ , $60=35+x$ .

STEP 1

Assumptions
1. We are solving for $x$ in each of the given equations separately.
2. Each equation represents a basic algebraic problem.
a) $x + 8 = 60$

STEP 2

Subtract 8 from both sides of the equation to isolate $x$ .
$x + 8 - 8 = 60 - 8$

STEP 3

Simplify both sides to find the value of $x$ .
$x = 52$
b) $\frac{x}{4} = 50$

STEP 4

Multiply both sides of the equation by 4 to isolate $x$ .
$4 \cdot \frac{x}{4} = 50 \cdot 4$

STEP 5

Simplify both sides to find the value of $x$ .
$x = 200$
d) $x^{2} = 400$

STEP 6

Take the square root of both sides of the equation to solve for $x$ .
$\sqrt{x^{2}} = \sqrt{400}$

STEP 7

Simplify both sides to find the values of $x$ .
$x = \pm 20$
e) $54 = 9x$

STEP 8

Divide both sides of the equation by 9 to isolate $x$ .
$\frac{54}{9} = \frac{9x}{9}$

STEP 9

Simplify both sides to find the value of $x$ .
$x = 6$
f) $60 = 35 + x$

STEP 10

Subtract 35 from both sides of the equation to isolate $x$ .
$60 - 35 = 35 + x - 35$

STEP 11

Simplify both sides to find the value of $x$ .
$x = 25$
The solutions are: a) $x = 52$ b) $x = 200$ d) $x = \pm 20$ e) $x = 6$ f) $x = 25$

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Solve for $x$ : $x+8=60$ , $\frac{x}{4}=50$ , $x^{2}=400$ , $54=9 x$ , $60=35+x$ .

STEP 1

Assumptions
1. We are solving for $x$ in each of the given equations separately.
2. Each equation represents a basic algebraic problem.
a) $x + 8 = 60$

STEP 2

Subtract 8 from both sides of the equation to isolate $x$ .
$x + 8 - 8 = 60 - 8$

STEP 3

Simplify both sides to find the value of $x$ .
$x = 52$
b) $\frac{x}{4} = 50$

STEP 4

Multiply both sides of the equation by 4 to isolate $x$ .
$4 \cdot \frac{x}{4} = 50 \cdot 4$

STEP 5

Simplify both sides to find the value of $x$ .
$x = 200$
d) $x^{2} = 400$

STEP 6

Take the square root of both sides of the equation to solve for $x$ .
$\sqrt{x^{2}} = \sqrt{400}$

STEP 7

Simplify both sides to find the values of $x$ .
$x = \pm 20$
e) $54 = 9x$

STEP 8

Divide both sides of the equation by 9 to isolate $x$ .
$\frac{54}{9} = \frac{9x}{9}$

STEP 9

Simplify both sides to find the value of $x$ .
$x = 6$
f) $60 = 35 + x$

STEP 10

Subtract 35 from both sides of the equation to isolate $x$ .
$60 - 35 = 35 + x - 35$

STEP 11

Simplify both sides to find the value of $x$ .
$x = 25$
The solutions are: a) $x = 52$ b) $x = 200$ d) $x = \pm 20$ e) $x = 6$ f) $x = 25$

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Solve for xxx: x+8=60x+8=60x+8=60, x4=50\frac{x}{4}=504x​=50, x2=400x^{2}=400x2=400, 54=9x54=9 x54=9x, 60=35+x60=35+x60=35+x.

STEP 1

Assumptions1. We are solving for xxx in each of the given equations separately.2. Each equation represents a basic algebraic problem.a) x+8=60x + 8 = 60x+8=60

STEP 2

Subtract 8 from both sides of the equation to isolate xxx.x+8−8=60−8x + 8 - 8 = 60 - 8x+8−8=60−8

STEP 3

Simplify both sides to find the value of xxx.x=52x = 52x=52b) x4=50\frac{x}{4} = 504x​=50

STEP 4

Multiply both sides of the equation by 4 to isolate xxx.4⋅x4=50⋅44 \cdot \frac{x}{4} = 50 \cdot 44⋅4x​=50⋅4

STEP 5

Simplify both sides to find the value of xxx.x=200x = 200x=200d) x2=400x^{2} = 400x2=400

STEP 6

Take the square root of both sides of the equation to solve for xxx.x2=400\sqrt{x^{2}} = \sqrt{400}x2​=400​

STEP 7

Simplify both sides to find the values of xxx.x=±20x = \pm 20x=±20e) 54=9x54 = 9x54=9x

STEP 8

Divide both sides of the equation by 9 to isolate xxx.549=9x9\frac{54}{9} = \frac{9x}{9}954​=99x​

STEP 9

Simplify both sides to find the value of xxx.x=6x = 6x=6f) 60=35+x60 = 35 + x60=35+x

STEP 10

Subtract 35 from both sides of the equation to isolate xxx.60−35=35+x−3560 - 35 = 35 + x - 3560−35=35+x−35

STEP 11

Simplify both sides to find the value of xxx.x=25x = 25x=25The solutions are: a) x=52x = 52x=52 b) x=200x = 200x=200 d) x=±20x = \pm 20x=±20 e) x=6x = 6x=6 f) x=25x = 25x=25

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Solve for $x$ : $x+8=60$ , $\frac{x}{4}=50$ , $x^{2}=400$ , $54=9 x$ , $60=35+x$ .

Assumptions
1. We are solving for $x$ in each of the given equations separately.
2. Each equation represents a basic algebraic problem.
a) $x + 8 = 60$

Subtract 8 from both sides of the equation to isolate $x$ .
$x + 8 - 8 = 60 - 8$

Simplify both sides to find the value of $x$ .
$x = 52$
b) $\frac{x}{4} = 50$

Multiply both sides of the equation by 4 to isolate $x$ .
$4 \cdot \frac{x}{4} = 50 \cdot 4$

Simplify both sides to find the value of $x$ .
$x = 200$
d) $x^{2} = 400$

Take the square root of both sides of the equation to solve for $x$ .
$\sqrt{x^{2}} = \sqrt{400}$

Simplify both sides to find the values of $x$ .
$x = \pm 20$
e) $54 = 9x$

Divide both sides of the equation by 9 to isolate $x$ .
$\frac{54}{9} = \frac{9x}{9}$

Simplify both sides to find the value of $x$ .
$x = 6$
f) $60 = 35 + x$

Subtract 35 from both sides of the equation to isolate $x$ .
$60 - 35 = 35 + x - 35$

Simplify both sides to find the value of $x$ .
$x = 25$
The solutions are: a) $x = 52$ b) $x = 200$ d) $x = \pm 20$ e) $x = 6$ f) $x = 25$