Solved on Feb 28, 2024

Find the values of a, b, and c in the equation 9x17ya3xby2=cx5y7\frac{9 x^{17} y^{a}}{3 x^{b} y^{2}}=c x^{5} y^{7}.

STEP 1

Assumptions
1. We are given the equation 9x17ya3xby2=cx5y7\frac{9 x^{17} y^{a}}{3 x^{b} y^{2}}=c x^{5} y^{7}.
2. We need to find the values of aa, bb, and cc.
3. The properties of exponents will be used to solve for the variables.

STEP 2

First, simplify the coefficients and the xx terms on the left side of the equation by dividing them.
93=3\frac{9}{3} = 3
x17b=x17bx^{17 - b} = x^{17-b}

STEP 3

Now, simplify the yy terms on the left side of the equation by subtracting the exponents.
ya2=ya2y^{a - 2} = y^{a-2}

STEP 4

After simplification, rewrite the equation with the simplified terms.
3x17bya2=cx5y73 x^{17-b} y^{a-2} = c x^{5} y^{7}

STEP 5

To find the value of cc, equate the coefficients on both sides of the equation.
3=c3 = c

STEP 6

Now we know that c=3c = 3.

STEP 7

To find the value of bb, equate the exponents of xx on both sides of the equation.
17b=517 - b = 5

STEP 8

Solve for bb.
b=175b = 17 - 5

STEP 9

Calculate the value of bb.
b=12b = 12

STEP 10

To find the value of aa, equate the exponents of yy on both sides of the equation.
a2=7a - 2 = 7

STEP 11

Solve for aa.
a=7+2a = 7 + 2

STEP 12

Calculate the value of aa.
a=9a = 9
The values of the variables are a=9a = 9, b=12b = 12, and c=3c = 3.

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