Solved on Oct 23, 2023

Solve for pp in the equation (123+(1.57895)(p15))p=0(123+(-1.57895)(p-15)) p = 0.

STEP 1

Assumptions1. The equation is (123+(1.57895)(p15))p=0(123+(-1.57895)(p-15)) p =0 . We need to solve for pp

STEP 2

The given equation is a product of two terms equal to zero. According to the zero-product property, if a product of factors is zero, then at least one of the factors must be zero. So, we can set each factor equal to zero and solve for pp.
123+(1.57895)(p15)=0123+(-1.57895)(p-15) =0p=0p =0

STEP 3

Let's solve the first equation. Distribute 1.57895-1.57895 inside the parentheses.
1231.57895p+23.68425=0123 -1.57895p +23.68425 =0

STEP 4

Combine like terms.
1.57895p+146.68425=0-1.57895p +146.68425 =0

STEP 5

Subtract 146.68425146.68425 from both sides of the equation.
1.57895p=146.68425-1.57895p = -146.68425

STEP 6

Divide both sides of the equation by 1.57895-1.57895 to solve for pp.
p=146.684251.57895p = \frac{-146.68425}{-1.57895}

STEP 7

Calculate the value of pp.
p92.86p \approx92.86So, the solutions for the equation (123+(1.57895)(p15))p=0(123+(-1.57895)(p-15)) p =0 are p=0p =0 and p92.86p \approx92.86.

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