Solved on Feb 23, 2024

Find the value of $-9.4 \cdot 2.7$ .

STEP 1

Assumptions
1. We are multiplying two decimal numbers: $-9.4$ and $2.7$ .
2. The multiplication of two numbers with different signs (one positive and one negative) will result in a negative product.

STEP 2

First, we will ignore the signs of the numbers and simply multiply their absolute values.
$Absolute\, product = | -9.4 | \cdot | 2.7 |$

STEP 3

Now, calculate the product of the absolute values.
$Absolute\, product = 9.4 \cdot 2.7$

STEP 4

To multiply the decimals, we can first multiply them as if they were whole numbers and then place the decimal point in the product.
$940 \cdot 27 = 25380$

STEP 5

Count the total number of decimal places in the factors. There is one decimal place in $9.4$ and one decimal place in $2.7$ , making a total of two decimal places.

STEP 6

Place the decimal point in the product so that there are two decimal places in the result.
$Absolute\, product = 253.80$

STEP 7

Now, recall that the original numbers had different signs, so the product must be negative.
$Product = -Absolute\, product$

STEP 8

Write the final product with the correct sign.
$Product = -253.80$
Therefore, $-9.4 \cdot 2.7 = -253.80$ .

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Find the value of $-9.4 \cdot 2.7$ .

STEP 1

Assumptions
1. We are multiplying two decimal numbers: $-9.4$ and $2.7$ .
2. The multiplication of two numbers with different signs (one positive and one negative) will result in a negative product.

STEP 2

First, we will ignore the signs of the numbers and simply multiply their absolute values.
$Absolute\, product = | -9.4 | \cdot | 2.7 |$

STEP 3

Now, calculate the product of the absolute values.
$Absolute\, product = 9.4 \cdot 2.7$

STEP 4

To multiply the decimals, we can first multiply them as if they were whole numbers and then place the decimal point in the product.
$940 \cdot 27 = 25380$

STEP 5

Count the total number of decimal places in the factors. There is one decimal place in $9.4$ and one decimal place in $2.7$ , making a total of two decimal places.

STEP 6

Place the decimal point in the product so that there are two decimal places in the result.
$Absolute\, product = 253.80$

STEP 7

Now, recall that the original numbers had different signs, so the product must be negative.
$Product = -Absolute\, product$

STEP 8

Write the final product with the correct sign.
$Product = -253.80$
Therefore, $-9.4 \cdot 2.7 = -253.80$ .

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Find the value of −9.4⋅2.7-9.4 \cdot 2.7−9.4⋅2.7.

STEP 1

Assumptions1. We are multiplying two decimal numbers: −9.4-9.4−9.4 and 2.72.72.7.2. The multiplication of two numbers with different signs (one positive and one negative) will result in a negative product.

STEP 2

First, we will ignore the signs of the numbers and simply multiply their absolute values.Absolute product=∣−9.4∣⋅∣2.7∣Absolute\, product = | -9.4 | \cdot | 2.7 |Absoluteproduct=∣−9.4∣⋅∣2.7∣

STEP 3

Now, calculate the product of the absolute values.Absolute product=9.4⋅2.7Absolute\, product = 9.4 \cdot 2.7Absoluteproduct=9.4⋅2.7

STEP 4

To multiply the decimals, we can first multiply them as if they were whole numbers and then place the decimal point in the product.940⋅27=25380940 \cdot 27 = 25380940⋅27=25380

STEP 5

Count the total number of decimal places in the factors. There is one decimal place in 9.49.49.4 and one decimal place in 2.72.72.7, making a total of two decimal places.

STEP 6

Place the decimal point in the product so that there are two decimal places in the result.Absolute product=253.80Absolute\, product = 253.80Absoluteproduct=253.80

STEP 7

Now, recall that the original numbers had different signs, so the product must be negative.Product=−Absolute productProduct = -Absolute\, productProduct=−Absoluteproduct

STEP 8

Write the final product with the correct sign.Product=−253.80Product = -253.80Product=−253.80Therefore, −9.4⋅2.7=−253.80-9.4 \cdot 2.7 = -253.80−9.4⋅2.7=−253.80.

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Find the value of $-9.4 \cdot 2.7$ .

Assumptions
1. We are multiplying two decimal numbers: $-9.4$ and $2.7$ .
2. The multiplication of two numbers with different signs (one positive and one negative) will result in a negative product.

First, we will ignore the signs of the numbers and simply multiply their absolute values.
$Absolute\, product = | -9.4 | \cdot | 2.7 |$

Now, calculate the product of the absolute values.
$Absolute\, product = 9.4 \cdot 2.7$

To multiply the decimals, we can first multiply them as if they were whole numbers and then place the decimal point in the product.
$940 \cdot 27 = 25380$

Count the total number of decimal places in the factors. There is one decimal place in $9.4$ and one decimal place in $2.7$ , making a total of two decimal places.

Place the decimal point in the product so that there are two decimal places in the result.
$Absolute\, product = 253.80$

Now, recall that the original numbers had different signs, so the product must be negative.
$Product = -Absolute\, product$

Write the final product with the correct sign.
$Product = -253.80$
Therefore, $-9.4 \cdot 2.7 = -253.80$ .