Solved on Feb 06, 2024

Solve the exponential equation 9x=139^{x}=\frac{1}{\sqrt{3}} for the value of xx.

STEP 1

Assumptions
1. We are given the equation 9x=139^{x} = \frac{1}{\sqrt{3}}.
2. We need to solve for the variable xx.

STEP 2

We can rewrite the equation using properties of exponents to express both sides with the same base.
9x=(3)19^{x} = \left(\sqrt{3}\right)^{-1}

STEP 3

Since 99 is a power of 33, we can rewrite 99 as 323^2.
(32)x=(3)1\left(3^2\right)^{x} = \left(\sqrt{3}\right)^{-1}

STEP 4

We can use the property of exponents that states (ab)c=abc(a^b)^c = a^{bc} to simplify the left side of the equation.
32x=(3)13^{2x} = \left(\sqrt{3}\right)^{-1}

STEP 5

Now, we rewrite the square root of 33 as 33 raised to the power of 12\frac{1}{2}.
32x=(312)13^{2x} = \left(3^{\frac{1}{2}}\right)^{-1}

STEP 6

We can use the property of exponents that states (ab)c=abc(a^b)^c = a^{bc} to simplify the right side of the equation.
32x=3123^{2x} = 3^{-\frac{1}{2}}

STEP 7

Since the bases on both sides of the equation are now the same, we can set the exponents equal to each other.
2x=122x = -\frac{1}{2}

STEP 8

To solve for xx, we divide both sides of the equation by 22.
x=122x = \frac{-\frac{1}{2}}{2}

STEP 9

Simplify the right side of the equation by multiplying the numerator by the reciprocal of the denominator.
x=12×12x = -\frac{1}{2} \times \frac{1}{2}

STEP 10

Calculate the value of xx.
x=14x = -\frac{1}{4}
The solution to the equation 9x=139^{x} = \frac{1}{\sqrt{3}} is x=14x = -\frac{1}{4}.

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