Solved on Oct 27, 2023

Identify the reciprocal functions from the given equations: y=x2y=x^{2}, y=1x+4y=\frac{1}{x+4}, y=7xy=\frac{7}{x}, y=2x+5y=\frac{2}{x}+5, y=x8y=\frac{x}{8}, y=3x+1y=3 x+1.

STEP 1

Assumptions1. A reciprocal function is a function of the form y=ax+by = \frac{a}{x} + b, where aa and bb are constants, and xx is the variable. . The functions provided are in the correct form and are simplified.

STEP 2

We need to identify which of the given equations are in the form of a reciprocal function. We can do this by comparing each equation with the standard form of a reciprocal function.

STEP 3

The first equation is y=x2y = x^{2}. This is not in the form of a reciprocal function because the variable xx is not in the denominator.

STEP 4

The second equation is y=1x+4y = \frac{1}{x+4}. This is not in the form of a reciprocal function because there is a constant added to the variable xx in the denominator.

STEP 5

The third equation is y=7xy = \frac{7}{x}. This is in the form of a reciprocal function because the variable xx is in the denominator and there is a constant in the numerator.

STEP 6

The fourth equation is y=2x+5y = \frac{2}{x} +5. This is in the form of a reciprocal function because the variable xx is in the denominator and there is a constant in the numerator. The constant added to the fraction does not change the fact that this is a reciprocal function.

STEP 7

The fifth equation is y=xy = \frac{x}{}. This is not in the form of a reciprocal function because the variable xx is in the numerator.

STEP 8

The sixth equation is y=3x+1y =3x +1. This is not in the form of a reciprocal function because the variable xx is not in the denominator.
The equations that are reciprocal functions are y=7xy = \frac{7}{x} and y=2x+5y = \frac{2}{x} +5.

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