Solved on Nov 07, 2023

Use De Morgan's laws to write the negation of r(qp)\sim r \wedge(\sim q \rightarrow p), where \sim negates only simple statements.

STEP 1

Assumptions1. We are using De Morgan's laws to write the negation of the statement. . The given statement is r(qp)\sim r \wedge(\sim q \rightarrow p).
3. The symbol \sim negates only simple statements.

STEP 2

De Morgan's laws state that the negation of a conjunction is the disjunction of the negations, and the negation of a disjunction is the conjunction of the negations. In other words(AB)=AB\sim (A \wedge B) = \sim A \vee \sim B(AB)=AB\sim (A \vee B) = \sim A \wedge \sim B

STEP 3

We can apply De Morgan's law to the given statement. The negation of the given statement is(r(qp))\sim (\sim r \wedge(\sim q \rightarrow p))

STEP 4

Applying De Morgan's law, we get(r)(qp)\sim (\sim r) \vee \sim (\sim q \rightarrow p)

STEP 5

implify the statement. The negation of r\sim r is rr, and the negation of qp\sim q \rightarrow p is qpq \wedge \sim p.
r(qp)r \vee (q \wedge \sim p)So, the negation of r(qp)\sim r \wedge(\sim q \rightarrow p) is r(qp)r \vee (q \wedge \sim p).

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