Solved on Dec 06, 2023

Rewrite each equation in the form y=a(xh)2+ky=a(x-h)^2+k by completing the square: a) y=x2+6x1y=x^2+6x-1, b) y=x2+10x+20y=x^2+10x+20.

STEP 1

Assumptions
1. We need to rewrite the given quadratic equations in the form y=a(xh)2+k y = a(x-h)^2 + k .
2. This process involves completing the square for each equation.
3. Completing the square is a method used to create a perfect square trinomial from a quadratic equation.

STEP 2

Starting with equation (a) y=x2+6x1 y = x^2 + 6x - 1 , we will complete the square.

STEP 3

Identify the coefficient of x x which is 6 in this case.

STEP 4

Divide the coefficient of x x by 2 and square the result to find the number that will complete the square.
(62)2=32=9\left(\frac{6}{2}\right)^2 = 3^2 = 9

STEP 5

Add and subtract this number inside the equation to maintain equality.
y=x2+6x+991y = x^2 + 6x + 9 - 9 - 1

STEP 6

Now, group the perfect square trinomial and the constants together.
y=(x2+6x+9)91y = (x^2 + 6x + 9) - 9 - 1

STEP 7

Factor the perfect square trinomial.
y=(x+3)291y = (x + 3)^2 - 9 - 1

STEP 8

Combine the constants.
y=(x+3)210y = (x + 3)^2 - 10

STEP 9

Now we have equation (a) in the form y=a(xh)2+k y = a(x-h)^2 + k :
y=(x+3)210y = (x + 3)^2 - 10

STEP 10

Next, we will complete the square for equation (b) y=x2+10x+20 y = x^2 + 10x + 20 .

STEP 11

Identify the coefficient of x x which is 10 in this case.

STEP 12

Divide the coefficient of x x by 2 and square the result to find the number that will complete the square.
(102)2=52=25\left(\frac{10}{2}\right)^2 = 5^2 = 25

STEP 13

Add and subtract this number inside the equation to maintain equality.
y=x2+10x+2525+20y = x^2 + 10x + 25 - 25 + 20

STEP 14

Group the perfect square trinomial and the constants together.
y=(x2+10x+25)25+20y = (x^2 + 10x + 25) - 25 + 20

STEP 15

Factor the perfect square trinomial.
y=(x+5)225+20y = (x + 5)^2 - 25 + 20

STEP 16

Combine the constants.
y=(x+5)25y = (x + 5)^2 - 5

STEP 17

Now we have equation (b) in the form y=a(xh)2+k y = a(x-h)^2 + k :
y=(x+5)25y = (x + 5)^2 - 5
The solutions for the given quadratic equations in the form y=a(xh)2+k y = a(x-h)^2 + k are:
a) y=(x+3)210 y = (x + 3)^2 - 10
b) y=(x+5)25 y = (x + 5)^2 - 5

Was this helpful?
banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ContactInfluencer programPolicyTerms
TwitterInstagramFacebookTikTokDiscord