Solved on Feb 24, 2024

Find the value of xx in an isosceles trapezoid VWXYVWXY where VX=3x+85VX=3x+85 and WY=4x+68WY=4x+68.

STEP 1

Assumptions
1. Quadrilateral VWXYVWXY is an isosceles trapezoid.
2. The lengths of the non-parallel sides (legs) of an isosceles trapezoid are equal.
3. VX=3x+85VX = 3x + 85 is the length of one leg.
4. WY=4x+68WY = 4x + 68 is the length of the other leg.

STEP 2

Since VWXYVWXY is an isosceles trapezoid, the lengths of its legs VXVX and WYWY are equal.
VX=WYVX = WY

STEP 3

Substitute the given expressions for VXVX and WYWY into the equation from STEP_2.
(3x+85)=(4x+68)(3x + 85) = (4x + 68)

STEP 4

To find the value of xx, we need to solve the equation for xx. Start by subtracting 3x3x from both sides of the equation to get the xx terms on one side.
85=x+6885 = x + 68

STEP 5

Now subtract 6868 from both sides of the equation to isolate xx.
8568=x85 - 68 = x

STEP 6

Calculate the value of xx.
x=8568=17x = 85 - 68 = 17
The value of xx is 17.

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