Solved on Mar 09, 2024

Phyllis invested 12,000withaportionearning12,000 with a portion earning 4.5\%interestandtherestearning interest and the rest earning 4\%interest.After1year,thetotalinterestearnedwas interest. After 1 year, the total interest earned was \525 525. Find the amount invested at each rate.

STEP 1

Question: Convert the simple interest rate of 412%4\frac{1}{2}\% to decimal form.
A) 0.045 B) 0.45 C) 4.5 D) 0.0045
Answer: A)

STEP 2

Question: If xx is the amount invested at the rate of 412%4\frac{1}{2}\%, which of the following represents the interest earned from this portion after 1 year?
A) x×0.45x \times 0.45 B) x×0.045x \times 0.045 C) x×4.5x \times 4.5 D) x×0.0045x \times 0.0045
Answer: B)

STEP 3

Question: If the total amount invested is 12,000and12,000 and x is the amount invested at 412%4\frac{1}{2}\%, how much is invested at the rate of 4%4\%?
A) 12,000+x12,000 + x B) 12,000x12,000 - x C) 4%×x4\% \times x D) 4%×(12,000x)4\% \times (12,000 - x)
Answer: B)

STEP 4

Question: What is the correct equation to represent the total interest earned from both investments after 1 year?
A) 525=x×0.045+(12,000+x)×0.04525 = x \times 0.045 + (12,000 + x) \times 0.04 B) 525=x×0.045+12,000×0.04525 = x \times 0.045 + 12,000 \times 0.04 C) 525=x×0.045+(12,000x)×0.04525 = x \times 0.045 + (12,000 - x) \times 0.04 D) 525=x×0.04+(12,000x)×0.045525 = x \times 0.04 + (12,000 - x) \times 0.045
Answer: C)

STEP 5

Question: Solve the equation 45=0.005x45 = 0.005x for xx.
A) x=9,000x = 9,000 B) x=900x = 900 C) x=90x = 90 D) x=9x = 9
Answer: A)

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