Solved on Sep 03, 2023

Multiply the given rational numbers $\left(3 \frac{1}{10}\right)(-6)\left(\frac{5}{12}\right)$ to find the product.

STEP 1

Assumptions1. We are given three numbers $3 \frac{1}{10}$ , $-6$ , and $\frac{5}{12}$ . . We need to find the product of these three numbers.

STEP 2

First, convert the mixed number $\frac{1}{10}$ to an improper fraction.
$\frac{1}{10} = \frac{31}{10}$

STEP 3

Now, we multiply the three numbers together. $\left(\frac{31}{10}\right)(-6)\left(\frac{5}{12}\right)$

STEP 4

We can rearrange the multiplication to make the calculation easier.
$\left(\frac{31}{10}\right)\left(\frac{}{12}\right)(-6)$

STEP 5

Now, multiply the two fractions together.
$\left(\frac{31}{10}\right)\left(\frac{5}{12}\right) = \frac{155}{120}$

STEP 6

implify the fraction $\frac{155}{120}$ to its lowest terms.
$\frac{155}{120} = \frac{31}{24}$

STEP 7

Finally, multiply the simplified fraction with $-6$ .
$\left(\frac{31}{24}\right)(-6) = -\frac{186}{24}$

STEP 8

implify the fraction $-\frac{186}{24}$ to its lowest terms.
$-\frac{186}{24} = -\frac{31}{4} = -7 \frac{3}{4}$ Therefore, the product of $\left(3 \frac{1}{10}\right)(-6)\left(\frac{5}{12}\right)$ is $-7 \frac{3}{4}$ .

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Multiply the given rational numbers $\left(3 \frac{1}{10}\right)(-6)\left(\frac{5}{12}\right)$ to find the product.

STEP 1

Assumptions1. We are given three numbers $3 \frac{1}{10}$ , $-6$ , and $\frac{5}{12}$ . . We need to find the product of these three numbers.

STEP 2

First, convert the mixed number $\frac{1}{10}$ to an improper fraction.
$\frac{1}{10} = \frac{31}{10}$

STEP 3

Now, we multiply the three numbers together. $\left(\frac{31}{10}\right)(-6)\left(\frac{5}{12}\right)$

STEP 4

We can rearrange the multiplication to make the calculation easier.
$\left(\frac{31}{10}\right)\left(\frac{}{12}\right)(-6)$

STEP 5

Now, multiply the two fractions together.
$\left(\frac{31}{10}\right)\left(\frac{5}{12}\right) = \frac{155}{120}$

STEP 6

implify the fraction $\frac{155}{120}$ to its lowest terms.
$\frac{155}{120} = \frac{31}{24}$

STEP 7

Finally, multiply the simplified fraction with $-6$ .
$\left(\frac{31}{24}\right)(-6) = -\frac{186}{24}$

STEP 8

implify the fraction $-\frac{186}{24}$ to its lowest terms.
$-\frac{186}{24} = -\frac{31}{4} = -7 \frac{3}{4}$ Therefore, the product of $\left(3 \frac{1}{10}\right)(-6)\left(\frac{5}{12}\right)$ is $-7 \frac{3}{4}$ .

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Multiply the given rational numbers (3110)(−6)(512)\left(3 \frac{1}{10}\right)(-6)\left(\frac{5}{12}\right)(3101​)(−6)(125​) to find the product.

STEP 1

Assumptions1. We are given three numbers 31103 \frac{1}{10}3101​, −6-6−6, and 512\frac{5}{12}125​. . We need to find the product of these three numbers.

STEP 2

First, convert the mixed number 110 \frac{1}{10}101​ to an improper fraction.110=3110 \frac{1}{10} = \frac{31}{10}101​=1031​

STEP 3

Now, we multiply the three numbers together.(3110)(−6)(512)\left(\frac{31}{10}\right)(-6)\left(\frac{5}{12}\right)(1031​)(−6)(125​)

STEP 4

We can rearrange the multiplication to make the calculation easier.(3110)(12)(−6)\left(\frac{31}{10}\right)\left(\frac{}{12}\right)(-6)(1031​)(12​)(−6)

STEP 5

Now, multiply the two fractions together.(3110)(512)=155120\left(\frac{31}{10}\right)\left(\frac{5}{12}\right) = \frac{155}{120}(1031​)(125​)=120155​

STEP 6

implify the fraction 155120\frac{155}{120}120155​ to its lowest terms.155120=3124\frac{155}{120} = \frac{31}{24}120155​=2431​

STEP 7

Finally, multiply the simplified fraction with −6-6−6.(3124)(−6)=−18624\left(\frac{31}{24}\right)(-6) = -\frac{186}{24}(2431​)(−6)=−24186​

STEP 8

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Multiply the given rational numbers $\left(3 \frac{1}{10}\right)(-6)\left(\frac{5}{12}\right)$ to find the product.

Assumptions1. We are given three numbers $3 \frac{1}{10}$ , $-6$ , and $\frac{5}{12}$ . . We need to find the product of these three numbers.

First, convert the mixed number $\frac{1}{10}$ to an improper fraction.
$\frac{1}{10} = \frac{31}{10}$

Now, we multiply the three numbers together. $\left(\frac{31}{10}\right)(-6)\left(\frac{5}{12}\right)$

We can rearrange the multiplication to make the calculation easier.
$\left(\frac{31}{10}\right)\left(\frac{}{12}\right)(-6)$

Now, multiply the two fractions together.
$\left(\frac{31}{10}\right)\left(\frac{5}{12}\right) = \frac{155}{120}$

implify the fraction $\frac{155}{120}$ to its lowest terms.
$\frac{155}{120} = \frac{31}{24}$

Finally, multiply the simplified fraction with $-6$ .
$\left(\frac{31}{24}\right)(-6) = -\frac{186}{24}$