Solved on Jan 25, 2024

Find the Cartesian product of set A with the union of sets B and C, given A={a,b},B={1,2}A=\{a, b\}, B=\{1,2\}, and C={2,3}C=\{2,3\}.

STEP 1

Assumptions
1. Set AA contains elements aa and bb.
2. Set BB contains elements 11 and 22.
3. Set CC contains elements 22 and 33.
4. The Cartesian product A×(BC)A \times (B \cup C) means all ordered pairs where the first element is from AA and the second element is from the union of BB and CC.

STEP 2

First, we need to find the union of sets BB and CC. The union of two sets includes all the distinct elements that are in either set.
BC={1,2}{2,3}B \cup C = \{1, 2\} \cup \{2, 3\}

STEP 3

Calculate the union of BB and CC by combining the elements from both sets, without repeating any elements.
BC={1,2,3}B \cup C = \{1, 2, 3\}

STEP 4

Now, we need to find the Cartesian product of set AA and the union of sets BB and CC.
A×(BC)={(x,y)xA and yBC}A \times (B \cup C) = \{(x, y) | x \in A \text{ and } y \in B \cup C\}

STEP 5

List all possible ordered pairs where the first element is from set AA and the second element is from the union BCB \cup C.
A×(BC)={(a,1),(a,2),(a,3),(b,1),(b,2),(b,3)}A \times (B \cup C) = \{(a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3)\}

STEP 6

Compare the result with the given options.
The correct answer is a. A×(BC)={(a,1),(a,2),(a,3),(b,1),(b,2),(b,3)}A \times(B \cup C)=\{(a, 1),(a, 2),(a, 3),(b, 1),(b, 2),(b, 3)\}.

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