Solved on Jan 18, 2024

Identify the starting value and rate of change of the linear equation y=7x2y=7x-2.

STEP 1

Assumptions
1. The equation given is in the form y=mx+b y = mx + b , which is the slope-intercept form of a linear equation.
2. In the slope-intercept form, m m represents the rate of change or slope, and b b represents the starting value or y-intercept.

STEP 2

Identify the slope (rate of change) in the given equation.
In the equation y=7x2 y = 7x - 2 , the coefficient of x x is 7 7 . This coefficient represents the slope or rate of change.

STEP 3

Identify the y-intercept (starting value) in the given equation.
In the equation y=7x2 y = 7x - 2 , the constant term is 2 -2 . This constant represents the y-intercept or starting value.

STEP 4

Match the identified slope and y-intercept with the given options.
The slope is 7 7 and the y-intercept is 2 -2 . Therefore, the starting value is 2 -2 and the rate of change is 7 7 .

STEP 5

Choose the correct option based on the identified slope and y-intercept.
The correct option is: A. Starting value: -2 Rate of change: 7

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