Solved on Feb 21, 2024

Find the equation that correctly expresses $r$ as the subject of $S=800(1-r)$ .
A. $r=\frac{800-S}{800}$ B. $r=\frac{S-800}{800}$ C. $r=800-S$ D. $r=S-800$

STEP 1

Assumptions
1. The given equation is $S=800(1-r)$ .
2. We need to solve for $r$ making it the subject of the equation.

STEP 2

We start by expanding the right side of the equation to isolate the term containing $r$ .
$S = 800 - 800r$

STEP 3

Next, we want to get the term with $r$ on one side of the equation by itself. To do this, we subtract $800$ from both sides of the equation.
$S - 800 = -800r$

STEP 4

Now, we need to isolate $r$ by dividing both sides of the equation by $-800$ .
$\frac{S - 800}{-800} = r$

STEP 5

Since dividing by $-1$ inverts the sign of the numerator, we can rewrite the equation as:
$r = \frac{800 - S}{800}$

STEP 6

Comparing the result with the given options, we find that the correct equation is:
$r = \frac{800 - S}{800}$
This corresponds to option A.
The correct equation that shows $r$ as the subject of the given equation is option A: $r=\frac{800-S}{800}$ .

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Find the equation that correctly expresses $r$ as the subject of $S=800(1-r)$ .
A. $r=\frac{800-S}{800}$ B. $r=\frac{S-800}{800}$ C. $r=800-S$ D. $r=S-800$

STEP 1

Assumptions
1. The given equation is $S=800(1-r)$ .
2. We need to solve for $r$ making it the subject of the equation.

STEP 2

We start by expanding the right side of the equation to isolate the term containing $r$ .
$S = 800 - 800r$

STEP 3

Next, we want to get the term with $r$ on one side of the equation by itself. To do this, we subtract $800$ from both sides of the equation.
$S - 800 = -800r$

STEP 4

Now, we need to isolate $r$ by dividing both sides of the equation by $-800$ .
$\frac{S - 800}{-800} = r$

STEP 5

Since dividing by $-1$ inverts the sign of the numerator, we can rewrite the equation as:
$r = \frac{800 - S}{800}$

STEP 6

Comparing the result with the given options, we find that the correct equation is:
$r = \frac{800 - S}{800}$
This corresponds to option A.
The correct equation that shows $r$ as the subject of the given equation is option A: $r=\frac{800-S}{800}$ .

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Find the equation that correctly expresses rrr as the subject of S=800(1−r)S=800(1-r)S=800(1−r).A. r=800−S800r=\frac{800-S}{800}r=800800−S​ B. r=S−800800r=\frac{S-800}{800}r=800S−800​ C. r=800−Sr=800-Sr=800−S D. r=S−800r=S-800r=S−800

STEP 1

Assumptions1. The given equation is S=800(1−r)S=800(1-r)S=800(1−r).2. We need to solve for rrr making it the subject of the equation.

STEP 2

We start by expanding the right side of the equation to isolate the term containing rrr.S=800−800rS = 800 - 800rS=800−800r

STEP 3

Next, we want to get the term with rrr on one side of the equation by itself. To do this, we subtract 800800800 from both sides of the equation.S−800=−800rS - 800 = -800rS−800=−800r

STEP 4

Now, we need to isolate rrr by dividing both sides of the equation by −800-800−800.S−800−800=r\frac{S - 800}{-800} = r−800S−800​=r

STEP 5

Since dividing by −1-1−1 inverts the sign of the numerator, we can rewrite the equation as:r=800−S800r = \frac{800 - S}{800}r=800800−S​

STEP 6

Comparing the result with the given options, we find that the correct equation is:r=800−S800r = \frac{800 - S}{800}r=800800−S​This corresponds to option A.The correct equation that shows rrr as the subject of the given equation is option A: r=800−S800r=\frac{800-S}{800}r=800800−S​.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Find the equation that correctly expresses $r$ as the subject of $S=800(1-r)$ .
A. $r=\frac{800-S}{800}$ B. $r=\frac{S-800}{800}$ C. $r=800-S$ D. $r=S-800$

Assumptions
1. The given equation is $S=800(1-r)$ .
2. We need to solve for $r$ making it the subject of the equation.

We start by expanding the right side of the equation to isolate the term containing $r$ .
$S = 800 - 800r$

Next, we want to get the term with $r$ on one side of the equation by itself. To do this, we subtract $800$ from both sides of the equation.
$S - 800 = -800r$

Now, we need to isolate $r$ by dividing both sides of the equation by $-800$ .
$\frac{S - 800}{-800} = r$

Since dividing by $-1$ inverts the sign of the numerator, we can rewrite the equation as:
$r = \frac{800 - S}{800}$

Comparing the result with the given options, we find that the correct equation is:
$r = \frac{800 - S}{800}$
This corresponds to option A.
The correct equation that shows $r$ as the subject of the given equation is option A: $r=\frac{800-S}{800}$ .