Solved on Nov 01, 2023

Given $x=y^2$ , find the missing values in the table: $\begin{array}{|c|c|} \hline x & y \\ \hline 0 & \text{?} \\ \hline \text{?} & 6 \\ \hline 4 & \text{?} \\ \hline \end{array}$ . Reduce all fractions to lowest terms.

STEP 1

Assumptions1. The given equation is $x=y^{}$ . . We need to find the missing $y$ values when $x$ is given and vice versa.
3. If multiple solutions exist, we only need to identify one.

STEP 2

Let's start by finding the missing $y$ value when $x=0$ . We can do this by substituting $x=0$ into the equation $x=y^{2}$ and solving for $y$ .
$0 = y^{2}$

STEP 3

Now, solve the equation for $y$ .
$y = \sqrt{0}$

STEP 4

Calculate the value of $y$ .
$y =0$

STEP 5

Next, let's find the missing $x$ value when $y=36$ . We can do this by substituting $y=36$ into the equation $x=y^{2}$ and solving for $x$ .
$x = (36)^{2}$

STEP 6

Calculate the value of $x$ .
$x =1296$

STEP 7

Finally, let's find the missing $y$ value when $x=4$ . We can do this by substituting $x=4$ into the equation $x=y^{2}$ and solving for $y$ .
$4 = y^{2}$

STEP 8

Now, solve the equation for $y$ .
$y = \sqrt{4}$

STEP 9

Calculate the value of $y$ .
$y =2$ So, the completed table is\begin{array}{|c|c|} \hlinex & y \\ \hline & \\ \hline1296 &36 \\ \hline4 &2 \\ \hline\end{array}

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Given $x=y^2$ , find the missing values in the table: $\begin{array}{|c|c|} \hline x & y \\ \hline 0 & \text{?} \\ \hline \text{?} & 6 \\ \hline 4 & \text{?} \\ \hline \end{array}$ . Reduce all fractions to lowest terms.

STEP 1

Assumptions1. The given equation is $x=y^{}$ . . We need to find the missing $y$ values when $x$ is given and vice versa.
3. If multiple solutions exist, we only need to identify one.

STEP 2

Let's start by finding the missing $y$ value when $x=0$ . We can do this by substituting $x=0$ into the equation $x=y^{2}$ and solving for $y$ .
$0 = y^{2}$

STEP 3

Now, solve the equation for $y$ .
$y = \sqrt{0}$

STEP 4

Calculate the value of $y$ .
$y =0$

STEP 5

Next, let's find the missing $x$ value when $y=36$ . We can do this by substituting $y=36$ into the equation $x=y^{2}$ and solving for $x$ .
$x = (36)^{2}$

STEP 6

Calculate the value of $x$ .
$x =1296$

STEP 7

Finally, let's find the missing $y$ value when $x=4$ . We can do this by substituting $x=4$ into the equation $x=y^{2}$ and solving for $y$ .
$4 = y^{2}$

STEP 8

Now, solve the equation for $y$ .
$y = \sqrt{4}$

STEP 9

Calculate the value of $y$ .
$y =2$ So, the completed table is\begin{array}{|c|c|} \hlinex & y \\ \hline & \\ \hline1296 &36 \\ \hline4 &2 \\ \hline\end{array}

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Given x=y2x=y^2x=y2, find the missing values in the table: xy0??64?\begin{array}{|c|c|} \hline x & y \\ \hline 0 & \text{?} \\ \hline \text{?} & 6 \\ \hline 4 & \text{?} \\ \hline \end{array}x0?4​y?6?​​. Reduce all fractions to lowest terms.

STEP 1

Assumptions1. The given equation is x=yx=y^{}x=y. . We need to find the missing yyy values when xxx is given and vice versa.3. If multiple solutions exist, we only need to identify one.

STEP 2

Let's start by finding the missing yyy value when x=0x=0x=0. We can do this by substituting x=0x=0x=0 into the equation x=y2x=y^{2}x=y2 and solving for yyy.0=y20 = y^{2}0=y2

STEP 3

Now, solve the equation for yyy.y=0y = \sqrt{0}y=0​

STEP 4

Calculate the value of yyy.y=0y =0y=0

STEP 5

Next, let's find the missing xxx value when y=36y=36y=36. We can do this by substituting y=36y=36y=36 into the equation x=y2x=y^{2}x=y2 and solving for xxx.x=(36)2x = (36)^{2}x=(36)2

STEP 6

Calculate the value of xxx.x=1296x =1296x=1296

STEP 7

Finally, let's find the missing yyy value when x=4x=4x=4. We can do this by substituting x=4x=4x=4 into the equation x=y2x=y^{2}x=y2 and solving for yyy.4=y24 = y^{2}4=y2

STEP 8

Now, solve the equation for yyy.y=4y = \sqrt{4}y=4​

STEP 9

Calculate the value of yyy.y=2y =2y=2So, the completed table is\begin{array}{|c|c|} \hlinex & y \\ \hline & \\ \hline1296 &36 \\ \hline4 &2 \\ \hline\end{array}

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Given $x=y^2$ , find the missing values in the table: $\begin{array}{|c|c|} \hline x & y \\ \hline 0 & \text{?} \\ \hline \text{?} & 6 \\ \hline 4 & \text{?} \\ \hline \end{array}$ . Reduce all fractions to lowest terms.

Assumptions1. The given equation is $x=y^{}$ . . We need to find the missing $y$ values when $x$ is given and vice versa.
3. If multiple solutions exist, we only need to identify one.

Let's start by finding the missing $y$ value when $x=0$ . We can do this by substituting $x=0$ into the equation $x=y^{2}$ and solving for $y$ .
$0 = y^{2}$

Now, solve the equation for $y$ .
$y = \sqrt{0}$

Calculate the value of $y$ .
$y =0$

Next, let's find the missing $x$ value when $y=36$ . We can do this by substituting $y=36$ into the equation $x=y^{2}$ and solving for $x$ .
$x = (36)^{2}$

Calculate the value of $x$ .
$x =1296$

Finally, let's find the missing $y$ value when $x=4$ . We can do this by substituting $x=4$ into the equation $x=y^{2}$ and solving for $y$ .
$4 = y^{2}$

Now, solve the equation for $y$ .
$y = \sqrt{4}$

Calculate the value of $y$ .
$y =2$ So, the completed table is\begin{array}{|c|c|} \hlinex & y \\ \hline & \\ \hline1296 &36 \\ \hline4 &2 \\ \hline\end{array}